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To: python-list@python.org
From: Terry Reedy <tjreedy@udel.edu>
Subject: Re: Windows subprocess.call problem
Date: Mon, 21 Jan 2013 18:38:27 -0500
References: <CAAPnF_XoeAQLqOXSWVF05sazUy6jtqSCSv18r7SL+18AqqbwmQ@mail.gmail.com> <50FD3CCD.4060707@davea.name> <CAAPnF_XpdmDB=kfHg8MS=YWybgCf-ng_NpMhjaTgxnvbxRJC6A@mail.gmail.com>
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Xref: csiph.com comp.lang.python:37234

On 1/21/2013 6:22 PM, Tom Borkin wrote:
> nobody@nowhere.com <mailto:nobody@nowhere.com> had an excellent
> suggestion that worked right off the bat and achieved exactly what I was
> after. Thanks all!

And what was it?

>
> On Mon, Jan 21, 2013 at 9:04 AM, Dave Angel <d@davea.name
> <mailto:d@davea.name>> wrote:
>
>     On 01/21/2013 06:25 AM, Tom Borkin wrote:
>
>         Hi;
>         I have this code:
>         <snip>
>
>         for song in my_songs:
>             subprocess.call(['notepad.exe'__, '%s.txt' % song])
>             print song
>
>         It opens the first song and hangs on subsequent songs. It
>         doesn't open the
>         next song or execute the print until I have closed the first
>         one. I want it
>         to open all in the list, one after another, so I have all those
>         songs
>         available. Please advise.
>
>
>     Why not just pass all the filenames as parameters in one invocation
>     of notepad?  Assuming Notepad is written reasonably, that'll give it
>     all to you in one window, instead of opening many separate ones.



-- 
Terry Jan Reedy