Path: csiph.com!au2pb.net!feeder.erje.net!1.eu.feeder.erje.net!feeds.phibee-telecom.net!newsfeed.xs4all.nl!newsfeed7.news.xs4all.nl!nzpost1.xs4all.net!not-for-mail Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.028 X-Spam-Evidence: '*H*': 0.94; '*S*': 0.00; 'subject:help': 0.07; 'sub': 0.09; 'def': 0.13; 'clear.': 0.16; 'pythonic': 0.16; 'sorting': 0.16; 'to:name:python-list@python.org': 0.20; '(a)': 0.22; 'this:': 0.23; 'second': 0.24; 'sort': 0.25; 'figure': 0.27; 'message-id:@mail.gmail.com': 0.27; 'this.': 0.28; 'initial': 0.28; 'field,': 0.30; "i'd": 0.31; 'another': 0.32; "can't": 0.32; 'common': 0.33; 'lists': 0.34; 'list': 0.34; 'received:google.com': 0.35; 'quite': 0.35; 'but': 0.36; 'there': 0.36; 'to:addr:python-list': 0.36; 'data': 0.39; 'to:addr:python.org': 0.40; 'some': 0.40; 'field': 0.60; 'hope': 0.61; 'show': 0.62 DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=gmail.com; s=20120113; h=mime-version:date:message-id:subject:from:to:content-type; bh=dQOQLzn3IG1xkLUcqcHjcgSTPeYEiHdk8yCmwxepWhI=; b=KvTk8YSdJ0E19gS4Ia3wP5IvCHDqJ6bjiiO3S9B/UBoXU1pDn4hcgGr1oNb360XdNr dSYqMskICWkCHAeNdV08OokIi8FIPu/f64tiWwoTT6jg03UEO+93x8xsi74B/bKPiiOU DWzWZe45ZGKHHmn3ma3E2XturPfTxee9jmHLGG/ViViVvXq5DAxy51eQPeGAa6MIEg7W +I+KaPmoi0pJmIhm+C3aT6xolJV3sokCSH2jJAfdlRh/mojFu3EeeowX4hztnh+HQbLa 5fsnG9lqsGVF4iztRC1ypIwBumMfAJd3b2dhBn76I2xIFRS1Rt+0WsL/mOHA4JkMSAoI uGHg== MIME-Version: 1.0 X-Received: by 10.55.204.66 with SMTP id r63mr32282324qki.10.1442961775526; Tue, 22 Sep 2015 15:42:55 -0700 (PDT) Date: Tue, 22 Sep 2015 18:42:55 -0400 Subject: sort help From: Larry Martell To: "python-list@python.org" Content-Type: text/plain; charset=UTF-8 X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.20+ Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Newsgroups: comp.lang.python Message-ID: Lines: 45 NNTP-Posting-Host: 2001:888:2000:d::a6 X-Trace: 1442962283 news.xs4all.nl 23766 [2001:888:2000:d::a6]:41284 X-Complaints-To: abuse@xs4all.nl Xref: csiph.com comp.lang.python:97002 I currently have 3 lists of lists and I sort them based on a common field into a single list like this: def GetObjKey(a): return a[2] sorted(a + b + c, key=GetObjKey) Which works just fine. But now, I need to have just the first list (a) also sub sorted by another field and I can't quite figure out how to do this. So for example, if my initial data was this (I'll only show the fields involved with the sort - the first number is a[2] above and the second is the new additional sorting field, only present in a) a[1, 4] a[1, 2] a[2, 3] a[2, 1] a[5, 6] a[5, 2] b[2] b[5] c[1] c[6] Then I'd want my sorted list to be this: a[1,2] a[1,4] c[1] a[2,1] a[2,3] b[2] a[5,2] a[5,6] b[5] c[6] I hope that's clear. So is there some pythonic way to sort this without resorting to a brute force old fashioned plow through the data?