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Date: Mon, 21 Jan 2013 07:25:06 -0400
Subject: Windows subprocess.call problem
From: Tom Borkin <borkintom@gmail.com>
To: python-list@python.org
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Hi;
I have this code:

#!/Python27/python
import os, subprocess, sys
lyrics_path = "/Users/Tom/Documents/lyrics"
os.chdir(lyrics_path)

songs = ['livin-la-vida-loca', 'whos-that-lady']
for song in songs:
  subprocess.call(['notepad.exe', '%s.txt' % song])
my_songs_path = "aa english lyrics"
os.chdir(my_songs_path)
for song in my_songs:
  subprocess.call(['notepad.exe', '%s.txt' % song])
  print song

It opens the first song and hangs on subsequent songs. It doesn't open the
next song or execute the print until I have closed the first one. I want it
to open all in the list, one after another, so I have all those songs
available. Please advise.
TIA,
Tom

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<div dir=3D"ltr"><div>Hi;</div><div>I have this code:</div><div>=A0</div><d=
iv>#!/Python27/python</div><div>import os, subprocess, sys<br></div><div>ly=
rics_path =3D &quot;/Users/Tom/Documents/lyrics&quot;<br>os.chdir(lyrics_pa=
th)</div>
<div>=A0</div><div>songs =3D [&#39;livin-la-vida-loca&#39;, &#39;whos-that-=
lady&#39;]<br>for song in songs:<br>=A0 subprocess.call([&#39;notepad.exe&#=
39;, &#39;%s.txt&#39; % song])<br></div><div>my_songs_path =3D &quot;aa eng=
lish lyrics&quot;<br>
os.chdir(my_songs_path)</div><div>for song in my_songs:<br>=A0 subprocess.c=
all([&#39;notepad.exe&#39;, &#39;%s.txt&#39; % song])<br>=A0 print song</di=
v><div>=A0</div><div>It opens the first song and hangs on subsequent songs.=
 It doesn&#39;t open the next song or execute the print until I have closed=
 the first one. I want it to open all in the list, one after another, so I =
have all those songs available. Please advise.</div>
<div>TIA,</div><div>Tom</div></div>

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