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Date: Sun, 19 Jul 2015 07:56:01 -0500
From: Tim Chase <python.list@tim.thechases.com>
To: python-list@python.org
Subject: Re: Devanagari int literals [was Re: Should non-security 2.7 bugs be fixed?]
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On 2015-07-19 14:45, Steven D'Aprano wrote:
>> ie we can now do
>>>>> =E0=A5=A7 + =E0=A5=A8 =20
>> 3 =20
>=20
> That is actually quite awesome, and I would support a new feature
> that set the numeric characters to a particular script, e.g. Latin,
> Arabic, Devanagari, whatever, and printed them in that same script.
> It seems unfortunate that =E0=A5=A7 + =E0=A5=A8 prints as 3 rather than =
=E0=A5=A9.
>=20
> Python already, and has for many years, supported non-ASCII digits
> in string conversions. This is in Python 2.4:
>=20
> py> int(u'=E0=A5=A7=E0=A5=A8') =20
> 12
> py> float(u'.=E0=A5=A7=E0=A5=A8') =20
> 0.12
>=20
> so the feature goes back a long time.

Agreed that it's pretty awesome.  It seems to have some holes though:

Python 3.4.2 (default, Oct  8 2014, 10:45:20)=20
[GCC 4.9.1] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> print('\N{VULGAR FRACTION ONE EIGHTH}')
=E2=85=9B
>>> print(float('\N{VULGAR FRACTION ONE EIGHTH}'))
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: could not convert string to float: '=E2=85=9B'
>>> print('\N{ROMAN NUMERAL NINE}')
=E2=85=A8
>>> int('\N{ROMAN NUMERAL NINE}')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: invalid literal for int() with base 10: '=E2=85=A8'
>>> print('\N{ROMAN NUMERAL TEN THOUSAND}')
=E2=86=82
>>> int('\N{ROMAN NUMERAL TEN THOUSAND}')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: invalid literal for int() with base 10: '=E2=86=82'

-tkc