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From: Ian Kelly <ian.g.kelly@gmail.com>
Date: Mon, 22 Jun 2015 16:48:23 -0600
Subject: Re: Simplest/Idiomatic way to count files in a directory (using pathlib)
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On Mon, Jun 22, 2015 at 4:33 PM, Travis Griggs <travisgriggs@gmail.com> wro=
te:
> <I should proof my posts before I send them, sorry>
>
> Subject nearly says it all.
>
> If i=E2=80=99m using pathlib, what=E2=80=99s the simplest/idiomatic way t=
o simply count how many files are in a given directory?
>
> I was surprised (at first) when
>
>    len(self.path.iterdir())
>
> didn=E2=80=99t work.

len doesn't work on iterators for a number of reasons:

* It would exhaust the iterator, preventing further use.
* The iterator is not necessarily finite.
* Even if it's finite, the length is not necessarily deterministic.
Consider this simple generator:

def gen():
    while random.randrange(2):
        yield 42

> I don=E2=80=99t see anything in the .stat() object that helps me.
>
> I could of course do the 4 liner:
>
>    count =3D 0
>    for _ in self.path.iterdir():
>        count +=3D 1
>    return count
>
> The following seems to obtuse/clever for its own good:
>
>    return sum(1 for _ in self.path.iterdir())

This is the usual idiom for counting the number of items yielded from
an iterator. Alternatively you can use len(list(self.path.iterdir()))
if you don't mind constructing a list of the entire directory listing.