Path: csiph.com!fu-berlin.de!uni-berlin.de!not-for-mail From: Emanuel Barry Newsgroups: comp.lang.python Subject: RE: subscripting Python 3 dicts/getting the only value in a Python 3 dict Date: Tue, 12 Jan 2016 12:00:06 -0500 Lines: 20 Message-ID: References: Mime-Version: 1.0 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable X-Trace: news.uni-berlin.de UKjgeRgP7tIwIQrTQzbeggbnN6q+bHbZMMBhaL5dz3Gw== Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.010 X-Spam-Evidence: '*H*': 0.98; '*S*': 0.00; 'subject:Python': 0.05; 'preferably': 0.05; 'subject:getting': 0.07; 'item,': 0.09; 'python': 0.10; '>>>': 0.15; 'subject: \n ': 0.15; 'value.': 0.15; 'received:io': 0.16; 'received:psf.io': 0.16; 'skip:` 20': 0.18; '>': 0.18; '>>>': 0.20; 'all,': 0.20; 'to:name:python-list@python.org': 0.20; 'problem:': 0.22; 'bit': 0.23; 'header:In-Reply-To:1': 0.24; 'equivalent': 0.27; 'dictionary': 0.29; 'seemingly': 0.29; 'subject:/': 0.30; 'code': 0.30; "i'd": 0.31; 'probably': 0.31; 'that,': 0.34; 'item': 0.35; 'but': 0.36; 'there': 0.36; 'to:addr:python-list': 0.36; 'subject:: ': 0.37; 'one,': 0.37; 'doing': 0.38; 'whatever': 0.39; 'subject:the': 0.39; 'to:addr:python.org': 0.40; 'where': 0.40; 'your': 0.60; 'is.': 0.63; 'obvious': 0.76; 'it"': 0.84; 'subject:value': 0.84; 'write:': 0.91 X-TMN: [BCQbA8PJOKW4wD9xX9AqqXRRDrLYJhej] X-Originating-Email: [vgr255@live.ca] Importance: Normal In-Reply-To: X-OriginalArrivalTime: 12 Jan 2016 17:00:06.0874 (UTC) FILETIME=[B02F4BA0:01D14D5A] X-Content-Filtered-By: Mailman/MimeDel 2.1.20+ X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.20+ Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Xref: csiph.com comp.lang.python:101553 > Hi all=2C >=20 > Seemingly simple problem: >=20 > There is a case in my code where I know a dictionary has only one item in= it. I want to get the value of that item=2C whatever the key is. >=20 > In Python2 I'd write: >=20 > >>> d =3D {"Wilf's Cafe": 1} > >>> d.values()[0] > 1 The equivalent in Python 3 is `list(d.values())[0]` > None of this feels like the "one=2C and preferably only one=2C obvious wa= y to do it" we all strive for. Any other ideas? If you feel like doing that=2C `for v in d.values(): pass` will set `v` to = your value. But it's a bit cryptic=2C so you can probably resort to the lis= t() alternative above :) - Emanuel =