Path: csiph.com!usenet.pasdenom.info!news.izac.org!ohm.izac.org!nntpfeed.proxad.net!proxad.net!feeder1-2.proxad.net!usenet-fr.net!nerim.net!novso.com!newsfeed.xs4all.nl!newsfeed2.news.xs4all.nl!xs4all!newsgate.cistron.nl!newsgate.news.xs4all.nl!post.news.xs4all.nl!not-for-mail
Date: Thu, 03 Oct 2013 19:44:27 +0100
From: MRAB <python@mrabarnett.plus.com>
User-Agent: Mozilla/5.0 (Windows NT 5.1; rv:24.0) Gecko/20100101 Thunderbird/24.0
MIME-Version: 1.0
To: python-list@python.org
Subject: Re: compare two list of dictionaries
References: <CADiHtmvUBMO4UrTow1xUbN7gG8TYs-WLqYh0-TKOVr78fhZw4Q@mail.gmail.com>
In-Reply-To: <CADiHtmvUBMO4UrTow1xUbN7gG8TYs-WLqYh0-TKOVr78fhZw4Q@mail.gmail.com>
Content-Type: text/plain; charset=ISO-8859-1; format=flowed
Content-Transfer-Encoding: 7bit
Precedence: list
Reply-To: python-list@python.org
Newsgroups: comp.lang.python
Message-ID: <mailman.693.1380825854.18130.python-list@python.org>
Lines: 134
NNTP-Posting-Host: 2001:888:2000:d::a6
Xref: csiph.com comp.lang.python:55439

On 03/10/2013 17:11, Mohan L wrote:
> Dear All,
>
> I have two list of dictionaries like below:
>
> In the below dictionaries the value of ip can be either hostname or ip
> address.
>
> output1=[
> {'count': 3 , 'ip': 'xxx.xx.xxx.1'},
> {'count': 4, 'ip': 'xxx.xx.xxx.2'},
> {'count': 8, 'ip': 'xxx.xx.xxx.3'},
> {'count': 10, 'ip': 'xxx.xx.xxx.4'},
> {'count': 212, 'ip': 'hostname1'},
> {'count': 27, 'ip': 'hostname2'},
> {'count': 513, 'ip': 'hostname3'},
> {'count': 98, 'ip': 'hostname4'},
> {'count': 1, 'ip': 'hostname10'},
> {'count': 2, 'ip': 'hostname8'},
> {'count': 3, 'ip': 'xxx.xx.xxx.11'},
> {'count': 90, 'ip': 'xxx.xx.xxx.12'},
> {'count': 12, 'ip': 'xxx.xx.xxx.13'},
> {'count': 21, 'ip': 'xxx.xx.xxx.14'},
> {'count': 54, 'ip': 'xxx.xx.xxx.15'},
> {'count': 34, 'ip': 'xxx.xx.xxx.16'},
> {'count': 11, 'ip': 'xxx.xx.xxx.17'},
> {'count': 2, 'ip': 'xxx.xx.xxx.18'},
> {'count': 19, 'ip': 'xxx.xx.xxx.19'},
> {'count': 21, 'ip': 'xxx.xx.xxx.20'},
> {'count': 25, 'ip': 'xxx.xx.xxx.21'},
> {'count': 31, 'ip': 'xxx.xx.xxx.22'},
> {'count': 43, 'ip': 'xxx.xx.xxx.23'},
> {'count': 46, 'ip': 'xxx.xx.xxx.24'},
> {'count': 80, 'ip': 'xxx.xx.xxx.25'},
> {'count': 91, 'ip': 'xxx.xx.xxx.26'},
> {'count': 90, 'ip': 'xxx.xx.xxx.27'},
> {'count': 10, 'ip': 'xxx.xx.xxx.28'},
> {'count': 3, 'ip': 'xxx.xx.xxx.29'}]
>
>
> In the below dictionaries have either hostname or ip or both.
>
> output2=(
>
> {'hostname': 'INNCHN01', 'ip_addr': 'xxx.xx.xxx.11'},
> {'hostname': 'HYDRHC02', 'ip_addr': 'xxx.xx.xxx.12'},
> {'hostname': 'INNCHN03', 'ip_addr': 'xxx.xx.xxx.13'},
> {'hostname': 'MUMRHC01', 'ip_addr': 'xxx.xx.xxx.14'},
> {'hostname': 'n/a', 'ip_addr': 'xxx.xx.xxx.15'},
> {'hostname': 'INNCHN05', 'ip_addr': 'xxx.xx.xxx.16'},
> {'hostname': 'hostname1', 'ip_addr': 'n/a'},
> {'hostname': 'hostname2', 'ip_addr': 'n/a'},
> {'hostname': 'hostname10', 'ip_addr': ''},
> {'hostname': 'hostname8', 'ip_addr': ''},
> {'hostname': 'hostname200', 'ip_addr': 'xxx.xx.xxx.200'},
> {'hostname': 'hostname300', 'ip_addr': 'xxx.xx.xxx.400'},
>
> )
>
> trying to get the following difference from the above dictionary
>
> 1). compare the value of 'ip' in output1 dictionary with either
> 'hostname' and 'ip_addr' output2 dictionary and print their
> intersection. Tried below code:
>
>
> for doc in output1:
>          for row in output2:
>                  if((row["hostname"] == doc["ip"]) or (row["ip_addr"] ==
> doc["ip"])):
>                          print doc["ip"],doc["count"]
>
> *output:*
> hostname1 212
> hostname2 27
> hostname10 1
> hostname8 2
> xxx.xx.xxx.11 3
> xxx.xx.xxx.12 90
> xxx.xx.xxx.13 12
> xxx.xx.xxx.14 21
> xxx.xx.xxx.15 54
> xxx.xx.xxx.16 34
>
1. Create a dict from output1 in which the key is the ip and the value
is the count.

2. Create a set from output2 containing all the hostnames and ip_addrs.

3. Get the intersection of the keys of the dict with the set.

4. Print the entries of the dict for each member of the intersection.

> 2). need to print the below output if the value of 'ip' in output1
> dictionary is not there in in output2 dictionary(ip/hostname which is
> there in output1 and not there in output2):
>
>   xxx.xx.xxx.1 3
>   xxx.xx.xxx.2 4
>   xxx.xx.xxx.3  8
>   xxx.xx.xxx.4  10
>   hostname3  513
>   hostname4  98
>   xxx.xx.xxx.17  11
>   xxx.xx.xxx.18  2
>   xxx.xx.xxx.19  19
>   xxx.xx.xxx.20  21
>   xxx.xx.xxx.21  25
>   xxx.xx.xxx.22  31
>   xxx.xx.xxx.23  43
>   xxx.xx.xxx.24  46
>   xxx.xx.xxx.25  80
>   xxx.xx.xxx.26  91
>   xxx.xx.xxx.27  90
>   xxx.xx.xxx.28  10
>   xxx.xx.xxx.29  3
>
1. Get the difference between the keys of the dict and the intersection.

2. Print the entries of the dict for each member of the difference.

> 3). Ip address with is there only in output2 dictionary.
>
> xxx.xx.xxx.200
> xxx.xx.xxx.400
>
1. Create a set from output2 containing all the ip_addrs.

2. Get the difference between the set and the keys of the dict created
from output1.

> Any help would be really appreciated. Thank you
>