Path: csiph.com!x330-a1.tempe.blueboxinc.net!usenet.pasdenom.info!weretis.net!feeder4.news.weretis.net!feeder.news-service.com!news2.euro.net!newsgate.cistron.nl!newsgate.news.xs4all.nl!post.news.xs4all.nl!not-for-mail Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.068 X-Spam-Evidence: '*H*': 0.86; '*S*': 0.00; '>>>>': 0.09; 'examples': 0.11; 'def': 0.15; 'subject:list': 0.18; 'to:2**1': 0.20; 'header :In-Reply-To:1': 0.22; 'skip:[ 10': 0.27; 'work.': 0.27; "skip:' 10": 0.30; 'to:addr:python-list': 0.33; 'header:User-Agent:1': 0.34; 'but': 0.37; 'subject:: ': 0.39; 'received:192': 0.39; 'else': 0.39; 'to:addr:python.org': 0.39; 'easily': 0.61; 'to:addr:latinmail.com': 0.84 Date: Tue, 16 Aug 2011 17:17:08 +0200 From: Laszlo Nagy User-Agent: Mozilla/5.0 (X11; U; Linux x86_64; en-US; rv:1.9.2.18) Gecko/20110617 Thunderbird/3.1.11 MIME-Version: 1.0 To: nn , python-list@python.org Subject: Re: testing if a list contains a sublist References: <8739h18rzj.fsf@dpt-info.u-strasbg.fr> <5e85b065-698e-4cd7-a409-d23618db1c3c@eb1g2000vbb.googlegroups.com> In-Reply-To: <5e85b065-698e-4cd7-a409-d23618db1c3c@eb1g2000vbb.googlegroups.com> Content-Type: text/plain; charset=ISO-8859-1; format=flowed Content-Transfer-Encoding: 7bit X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.12 Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Newsgroups: comp.lang.python Message-ID: Lines: 16 NNTP-Posting-Host: 2001:888:2000:d::a6 X-Trace: 1313507834 news.xs4all.nl 23874 [2001:888:2000:d::a6]:37472 X-Complaints-To: abuse@xs4all.nl Xref: x330-a1.tempe.blueboxinc.net comp.lang.python:11563 > That can be easily fixed: > >>>> def sublist(lst1, lst2): > s1 = ','.join(map(str, lst1)) > s2 = ','.join(map(str, lst2)) > return False if s2.find(s1)==-1 else True > > I don't know about best, but it works for the examples given. > For numbers, it will always work. But what about lst1 = [",",",,"] lst1 = [",",",",","]