Path: csiph.com!usenet.pasdenom.info!aioe.org!news.stack.nl!newsfeed.xs4all.nl!newsfeed2.news.xs4all.nl!xs4all!post.news.xs4all.nl!not-for-mail Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.005 X-Spam-Evidence: '*H*': 0.99; '*S*': 0.00; 'value,': 0.03; 'python:': 0.09; 'sure,': 0.09; 'subject:not': 0.11; 'received:74.55.86': 0.16; 'received:74.55.86.74': 0.16; 'received:smtp.webfaction.com': 0.16; 'received:webfaction.com': 0.16; 'sentinel': 0.16; 'setdefault': 0.16; 'subject:already': 0.16; 'subject:key': 0.16; 'thread-safe': 0.16; 'wrote:': 0.17; 'element': 0.17; '>>>': 0.18; 'header:In-Reply-To:1': 0.25; 'header:User-Agent:1': 0.26; 'am,': 0.27; 'guess': 0.27; 'chris': 0.28; "i'm": 0.29; 'sense': 0.31; 'to:addr:python-list': 0.33; 'subject:?': 0.35; 'add': 0.36; 'but': 0.36; 'subject:: ': 0.38; 'to:addr:python.org': 0.39; 'received:192': 0.39; 'received:192.168': 0.40; 'your': 0.60; 'dict,': 0.84; 'investigated': 0.84; 'subject:add': 0.91 Date: Sat, 19 Jan 2013 02:35:12 -0500 From: Mitya Sirenef User-Agent: Mozilla/5.0 (X11; Linux x86_64; rv:16.0) Gecko/20121011 Thunderbird/16.0.1 MIME-Version: 1.0 To: python-list@python.org Subject: Re: Safely add a key to a dict only if it does not already exist? References: <50fa1bf1$0$30003$c3e8da3$5496439d@news.astraweb.com> In-Reply-To: Content-Type: text/plain; charset=ISO-8859-1; format=flowed Content-Transfer-Encoding: 7bit X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.15 Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Newsgroups: comp.lang.python Message-ID: Lines: 19 NNTP-Posting-Host: 2001:888:2000:d::a6 X-Trace: 1358580916 news.xs4all.nl 6953 [2001:888:2000:d::a6]:42080 X-Complaints-To: abuse@xs4all.nl Xref: csiph.com comp.lang.python:37063 On 01/19/2013 02:27 AM, Vito De Tullio wrote: > Chris Rebert wrote: > >>> How can I add a key in a thread-safe manner? >> I'm not entirely sure, but have you investigated dict.setdefault() ? > but how setdefault makes sense in this context? It's used to set a default > value when you try to retrieve an element from the dict, not when you try to > set a new one ... > I guess setdefault with a sentinel default value, then set to your new value if d[k] is sentinel? - mitya -- Lark's Tongue Guide to Python: http://lightbird.net/larks/