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Subject: Re: datetime.datetime.today()
From: Michiel Overtoom <motoom@xs4all.nl>
In-Reply-To: <CANc-5Uz7bON+aXG1vmOpuVAqga9v8h+tLBjvWtDbWo6hF3OXTw@mail.gmail.com>
Date: Wed, 16 Sep 2015 17:01:39 +0200
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Xref: csiph.com comp.lang.python:96685


This bit me once. I was comparing a date to a datetime, both =
representing the same day, so I expected them to be the same, but I was =
wrong. What I should have done was extracting the date of the datetime =
with the .date() function, and only then compare it to the other date:

>>> import datetime
>>> a =3D datetime.datetime.today()
>>> a
datetime.datetime(2015, 9, 16, 16, 57, 45, 150069)
>>> b =3D datetime.date.today()
>>> a =3D=3D b
False
>>> a.date()
datetime.date(2015, 9, 16)
>>> a.date() =3D=3D b
True

Greetings,