Path: csiph.com!v102.xanadu-bbs.net!xanadu-bbs.net!feeder.erje.net!eu.feeder.erje.net!newsfeed.datemas.de!weretis.net!feeder4.news.weretis.net!feeds.phibee-telecom.net!newsfeed.xs4all.nl!newsfeed2a.news.xs4all.nl!xs4all!post.news.xs4all.nl!not-for-mail Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.002 X-Spam-Evidence: '*H*': 1.00; '*S*': 0.00; 'nested': 0.07; '[1,': 0.09; 'iterate': 0.09; 'received:80.91': 0.09; 'received:80.91.229': 0.09; 'received:gmane.org': 0.09; 'received:list': 0.09; 'solution,': 0.09; 'random': 0.14; '2],': 0.16; '[])': 0.16; 'received:80.91.229.3': 0.16; 'received:dip0.t-ipconnect.de': 0.16; 'received:plane.gmane.org': 0.16; 'received:t-ipconnect.de': 0.16; 'subject:sub': 0.16; 'succinct': 0.16; 'wrote:': 0.18; 'header:User-Agent:1': 0.23; 'skip:l 30': 0.24; 'least': 0.26; 'header:X-Complaints-To:1': 0.27; 'subject:list': 0.30; 'way?': 0.31; 'subject:all': 0.32; 'another': 0.32; "can't": 0.35; 'but': 0.35; 'really': 0.36; 'should': 0.36; 'two': 0.37; 'list': 0.37; 'to:addr:python-list': 0.38; 'list,': 0.38; 'to:addr:python.org': 0.39; 'received:org': 0.40; 'how': 0.40; 'numbers': 0.61; 'email addr:gmail.com': 0.63; 'provide': 0.64; 'them)': 0.84 X-Injected-Via-Gmane: http://gmane.org/ To: python-list@python.org From: Peter Otten <__peter__@web.de> Subject: Re: how to iterate all sub-element in a list Date: Fri, 31 Jan 2014 11:48:13 +0100 Organization: None References: <412b4d42-acba-4609-bd6d-e4d5c32db035@googlegroups.com> Mime-Version: 1.0 Content-Type: text/plain; charset="ISO-8859-1" Content-Transfer-Encoding: 7Bit X-Gmane-NNTP-Posting-Host: p50848b42.dip0.t-ipconnect.de User-Agent: KNode/4.7.3 X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.15 Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Newsgroups: comp.lang.python Message-ID: Lines: 15 NNTP-Posting-Host: 2001:888:2000:d::a6 X-Trace: 1391165287 news.xs4all.nl 2909 [2001:888:2000:d::a6]:44810 X-Complaints-To: abuse@xs4all.nl Xref: csiph.com comp.lang.python:65113 seaspeak@gmail.com wrote: > a list like L = [[1, 2], [3, 4, 5], [6]], which has > random numbers of list, which has random numbers. > > How do I get another list m = [1, 2, 3, 4, 5, 6] in a succinct way? ( or > iterate them) I should provide my own solution, but I really can't come > out with one. sum(L, []) list(itertools.chain.from_iterable(L)) but as a learning experience you should do this at least once with two nested for loops, then again with a single for loop and list.extend().