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Date: Thu, 16 Feb 2012 07:59:50 +0000
Subject: Re: Wanted: Criticism of code for a Python module, plus a Mac tester
From: Arnaud Delobelle <arnodel@gmail.com>
To: Ian Kelly <ian.g.kelly@gmail.com>
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On 16 February 2012 05:03, Ian Kelly <ian.g.kelly@gmail.com> wrote:
> On Wed, Feb 15, 2012 at 6:11 PM, HoneyMonster <someone@someplace.invalid>=
 wrote:
>> As to your first suggestion though, I am having some difficulty. Note
>> that the vulnerability rotates; i.e. CONDITIONS[4] is not the same as
>> CONDITIONS[0].
>> Is there a better way of doing it than a simple list.append()?
>
> Ah, it's more complicated than I realized. =C2=A0I believe this generates
> the correct result, although adding None to the dealers list is
> somewhat unsatisfactory:
>
> DEALERS =3D ["Dealer North", "Dealer East", "Dealer South", "Dealer West"=
, None]
> VULNERABILITIES =3D [
> =C2=A0 "Neither vulnerable", "North-South vulnerable",
> =C2=A0 "East-West vulnerable", "Both vulnerable",
> ]
> CONDITIONS =3D [(d, v) for (d, v) in zip(DEALERS * 4, VULNERABILITIES * 5=
) if d]

You could also do:

DEALERS =3D ["Dealer North", "Dealer East", "Dealer South", "Dealer West"]
VULNERABILITIES =3D [
=C2=A0 "Neither vulnerable", "North-South vulnerable",
=C2=A0 "East-West vulnerable", "Both vulnerable",
]
CONDITIONS =3D [
    (DEALERS[j], VULNERABILITIES[(i + j)%4])
    for i in range(4) for j in range(4)
]

If you don't care about the order in which the conditions are listed,
you could use

CONDITIONS =3D itertools.product(DEALERS, VULNERABILITIES)

(But maybe you do, I haven't looked at the code)

--=20
Arnaud