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Newsgroups: comp.lang.python
Date: Tue, 15 Jan 2013 12:29:28 -0800 (PST)
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Subject: Re: sqlite3 puzzle
From: llanitedave <llanitedave@veawb.coop>
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Xref: csiph.com comp.lang.python:36868

On Tuesday, January 15, 2013 9:13:13 AM UTC-8, Rob Day wrote:
> On 15 January 2013 15:51, llanitedave <llanitedave@veawb.coop> wrote:
> 
> > Thanks for the suggestion, Rob, but that didn't make any difference.  I've never had an issue with putting the execute object into a variable and calling "fetch" on that variable.
> 
> >
> 
> > I can accept reality if it turns out that foreign keys simply isn't enabled on the Python distribution of sqlite, although I don't know why that should be the case.  I'm just curious as to why it worked at first and then stopped working.
> 
> 
> 
> Well - you might be able to accept that, but I'm not sure I can! If it
> 
> was working before, it must be compiled in, and so it must be possible
> 
> to make it work again.
> 
> 
> 
> http://www.sqlite.org/foreignkeys.html#fk_enable seems to suggest that
> 
> "PRAGMA foreign_keys = ON" never returns anything, and it's only
> 
> "PRAGMA foreign_keys" which returns 0, 1 or None (when unsupported).
> 
> With that in mind, does the following code work?
> 
> 
> 
> # open database file
> 
> 
> 
> self.geologger_db = sqlite3.connect('geologger.mgc')
> 
> self.db_cursor = self.geologger_db.cursor()
> 
> self.db_cursor.execute("PRAGMA foreign_keys = ON")
> 
> self.db_cursor.execute("PRAGMA foreign_keys")
> 
> print self.db_cursor.fetchone()

"http://www.sqlite.org/foreignkeys.html#fk_enable seems to suggest that "PRAGMA foreign_keys = ON" never returns anything, and it's only "PRAGMA foreign_keys" which returns 0, 1 or None (when unsupported)."

That was it, exactly, Rob.  I don't know where I got the idea that I was getting  a '1' from the 'ON' command, although I was sure that I'd seen it.  But once I just called "foreign_key" it returned just fine.

Ummm...  Obviously I was up fiddling around too late.  Yeah, that's it.


Thanks!  It's solved now.