Path: csiph.com!usenet.pasdenom.info!aioe.org!news.stack.nl!newsfeed.xs4all.nl!newsfeed4.news.xs4all.nl!xs4all!newsgate.cistron.nl!newsgate.news.xs4all.nl!post.news.xs4all.nl!not-for-mail Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.014 X-Spam-Evidence: '*H*': 0.97; '*S*': 0.00; 'string.': 0.05; 'subject:Python': 0.06; 'cc:addr:python-list': 0.11; 'jan': 0.12; 'from:addr:rosuav': 0.16; 'from:name:chris angelico': 0.16; 'helps!': 0.16; 'igor': 0.16; 'integer,': 0.16; 'length.': 0.16; 'throw': 0.16; 'unexpected': 0.16; 'exception': 0.16; 'wrote:': 0.18; 'split': 0.19; 'cc:addr:python.org': 0.22; 'cc:2**0': 0.24; 'this:': 0.26; 'header:In-Reply-To:1': 0.27; 'field,': 0.30; 'message-id:@mail.gmail.com': 0.30; "i'm": 0.30; 'info.': 0.31; 'request,': 0.31; 'know.': 0.32; 'there,': 0.34; 'received:google.com': 0.35; 'there': 0.35; '14,': 0.36; 'subject:?': 0.36; 'two': 0.37; 'whatever': 0.38; 'pm,': 0.38; 'anything': 0.39; 'either': 0.39; 'space': 0.40; 'hope': 0.61; 'length': 0.61; "you're": 0.61; "you'll": 0.62; 'analysis': 0.75; 'safe;': 0.84; 'to:none': 0.92 DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=gmail.com; s=20120113; h=mime-version:in-reply-to:references:date:message-id:subject:from:cc :content-type; bh=PyYhk8lmG4ewuMdFCVKtW45L6S2QOXH20RmIkFJe54M=; b=uA6Ojah/CZPGtGQj8fFwphn+/fxZcr7wGdAkOUOMthjB+c8EIOCCNjxyQxkjirTR7O CWraQilLirjYvG3YPlJjh9+gA3iE94CPWFyzmcQAi/b1h+NyAIizbEqZ+KPfWvMGOX62 2Ignsb0lXCGnMDmCgBIzzEs9cTmexuUvw3YO3RSIs+uYqQC54MxkgHyeIjOa/i4Tcno4 B1o7W3QQkBnsz73xLK2ArtjNBzjjTWXcqWJr7oJqppI5uMIqWE20Qk453oKfgSrJvib9 YXngX9QQwqd9yUf7d5CDj9JqUU1ZgkqWRq3yfSKoLvaB02ip+sLnaYAM+nr2K4QQwqzY gR1g== MIME-Version: 1.0 X-Received: by 10.66.160.2 with SMTP id xg2mr356899pab.23.1389689898016; Tue, 14 Jan 2014 00:58:18 -0800 (PST) In-Reply-To: References: Date: Tue, 14 Jan 2014 19:58:17 +1100 Subject: Re: What's correct Python syntax? From: Chris Angelico Cc: "python-list@python.org" Content-Type: text/plain; charset=UTF-8 X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.15 Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Newsgroups: comp.lang.python Message-ID: Lines: 32 NNTP-Posting-Host: 2001:888:2000:d::a6 X-Trace: 1389690263 news.xs4all.nl 2858 [2001:888:2000:d::a6]:34452 X-Complaints-To: abuse@xs4all.nl Xref: csiph.com comp.lang.python:63877 On Tue, Jan 14, 2014 at 7:46 PM, Igor Korot wrote: > 192.168.1.6 > 192.168.1.7: ICMP echo request, id 100, seq 200, length 30 > > However, I don't need all the protocol info. All I'm interested in is > the last field, which is length. You can split on any string. If you're confident that this is the only instance of the word "length", you can split on that: for data in f: # This will throw an exception if there's no " length " # or if there are two of them. This means you're safe; # if anything unexpected happens, you'll know. _, length = data.split(" length ") # process length Alternatively, you can split on the space and take just the very last word: for data in f: length = data.split(" ")[-1] # process length Either way, the length will be a string. If you need it as an integer, just do this: length = int(length) >From there, you can do whatever analysis you need. Hope that helps! ChrisA