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Date: Tue, 20 Aug 2013 10:16:55 +0100
Subject: Re: Replace blanks with letter
From: =?ISO-8859-1?Q?F=E1bio_Santos?= <fabiosantosart@gmail.com>
To: eschneider92@comcast.net
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On 20 Aug 2013 09:42, <eschneider92@comcast.net> wrote:
>
> I'm trying to replace the blank(_) with the letter typed in by the user,
in the appropriate blank(_) spot where the letter should be (where is in
the letters list).
>
> letters='abcdefg'
> blanks='_ '*len(letters)
> print('type letter from a to g')
> print(blanks)
> input1=input()
> for i in range(len(letters)):
>     if letters[i] in input1:
>         blanks = blanks[:i] + letters[i] + blanks[i+1:]
>
>
> What am I doing wrong in this code?
>
> Thanks
> Eric

First, don't use range(len(iterable)). It's bad practise, and you will have
to use iterable[i] all the time. Try

for i, letter in enumerate(letters):

If you are modifying a string in-place, you could change it into a list,
then back.

blankslst = list(blanks)
...
blankslst[i] = letters[i]  # or 'letter' if you used enumerate()
...
blanks = ''.join(blankslst)

Now, why are you not printing the `blanks` string again?

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<p dir=3D"ltr"><br>
On 20 Aug 2013 09:42, &lt;<a href=3D"mailto:eschneider92@comcast.net">eschn=
eider92@comcast.net</a>&gt; wrote:<br>
&gt;<br>
&gt; I&#39;m trying to replace the blank(_) with the letter typed in by the=
 user, in the appropriate blank(_) spot where the letter should be (where i=
s in the letters list).<br>
&gt;<br>
&gt; letters=3D&#39;abcdefg&#39;<br>
&gt; blanks=3D&#39;_ &#39;*len(letters)<br>
&gt; print(&#39;type letter from a to g&#39;)<br>
&gt; print(blanks)<br>
&gt; input1=3Dinput()<br>
&gt; for i in range(len(letters)):<br>
&gt; =A0 =A0 if letters[i] in input1:<br>
&gt; =A0 =A0 =A0 =A0 blanks =3D blanks[:i] + letters[i] + blanks[i+1:]<br>
&gt;<br>
&gt;<br>
&gt; What am I doing wrong in this code?<br>
&gt;<br>
&gt; Thanks<br>
&gt; Eric</p>
<p dir=3D"ltr">First, don&#39;t use range(len(iterable)). It&#39;s bad prac=
tise, and you will have to use iterable[i] all the time. Try</p>
<p dir=3D"ltr">for i, letter in enumerate(letters):</p>
<p dir=3D"ltr">If you are modifying a string in-place, you could change it =
into a list, then back.</p>
<p dir=3D"ltr">blankslst =3D list(blanks)<br>
...<br>
blankslst[i] =3D letters[i]=A0 # or &#39;letter&#39; if you used enumerate(=
)<br>
...<br>
blanks =3D &#39;&#39;.join(blankslst)</p>
<p dir=3D"ltr">Now, why are you not printing the `blanks` string again?</p>

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