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From: Ian Kelly <ian.g.kelly@gmail.com>
Date: Wed, 1 Feb 2012 16:47:53 -0700
Subject: Re: Question about name scope
To: Ethan Furman <ethan@stoneleaf.us>
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Xref: x330-a1.tempe.blueboxinc.net comp.lang.python:19755

On Wed, Feb 1, 2012 at 4:41 PM, Ethan Furman <ethan@stoneleaf.us> wrote:
> I'm not sure what you mean by temporary:
>
> --> def f(x, y):
>
> ... =A0 =A0 frob =3D None
> ... =A0 =A0 loc =3D locals()
> ... =A0 =A0 loc[x] =3D y
> ... =A0 =A0 print(loc)
> ... =A0 =A0 print(locals())
> ... =A0 =A0 print(loc)
> ... =A0 =A0 print(locals())
> ...
> -->
> --> f('frob', 19)
> {'y': 19, 'x': 'frob', 'frob': 19}
> {'y': 19, 'x': 'frob', 'frob': None, 'loc': {...}}
> {'y': 19, 'x': 'frob', 'frob': None, 'loc': {...}}
> {'y': 19, 'x': 'frob', 'frob': None, 'loc': {...}}
>
> Seems to be stuck that way.

The first print is the one that is incorrect.  It suggests that the
local 'frob' has been changed to 19 as it has in the dict, but the
actual value of the local is still None.  The second print on
accurately reflect that.