Path: csiph.com!usenet.pasdenom.info!news.etla.org!news.stack.nl!newsfeed.xs4all.nl!newsfeed2.news.xs4all.nl!xs4all!newsgate.cistron.nl!newsgate.news.xs4all.nl!post.news.xs4all.nl!not-for-mail Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.048 X-Spam-Evidence: '*H*': 0.91; '*S*': 0.00; 'column': 0.07; 'indicating': 0.07; 'nested': 0.07; 'subject:would': 0.07; 'spaces': 0.09; 'subject:How': 0.10; 'code?': 0.16; 'loops': 0.16; 'accordingly.': 0.16; 'wrote:': 0.18; 'thu,': 0.19; 'print': 0.22; 'this:': 0.26; 'header:In-Reply-To:1': 0.27; 'strongly': 0.30; 'message-id:@mail.gmail.com': 0.30; "i'm": 0.30; 'easier': 0.31; 'reply.': 0.31; '25,': 0.31; 'with,': 0.31; 'basic': 0.35; 'board': 0.35; 'something': 0.35; 'received:google.com': 0.35; 'there': 0.35; 'subject:?': 0.36; 'should': 0.36; 'implement': 0.38; 'thank': 0.38; 'to:addr:python-list': 0.38; 'pm,': 0.38; 'little': 0.38; 'structure': 0.39; 'to:addr:python.org': 0.39; 'skip:p 20': 0.39; 'space': 0.40; 'how': 0.40; 'skip:u 10': 0.60; "you'll": 0.62; 'more': 0.64; 'jul': 0.74; 'square': 0.74; 'subject:this': 0.83; 'compact,': 0.84; 'labels.': 0.93; '2013': 0.98 DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=gmail.com; s=20120113; h=mime-version:in-reply-to:references:from:date:message-id:subject:to :content-type; bh=h6ycgIm+0OI1F55Gn0TM9ip61x9ukFQfZeeu+3ASNdo=; b=LlCaso1KOPL+S7EiNUE/VRM5wc41Ke1dckistXkwK7HFyykvdgcllwJQBMT6Ex2a1A g6xHUZmyF8C6RRpjKWbKUKCm9mAGlTpRjKSJYZR18686gYfeprFANC+n0ZvQiMVS9DbV YXkQJpN6o/OxUqLqn1NryOD4BeEo/nzv6MBFP7CILDTHwlZgKCCEGMRfRJiyBQtmNfwr B/zExvAymrDvgronlxy1kIibYdm2wGnAv0z06oqHXIUuMBfvbXFQzjavlYy+NHyOQ/Mf Lu38RVazsBXGfw+REsGPQYzkBBIZK4/s52RMBkPaeDAehVFMbaVHscMIZVaUMY8K3tMr XoKQ== X-Received: by 10.66.164.199 with SMTP id ys7mr5515707pab.104.1374811378779; Thu, 25 Jul 2013 21:02:58 -0700 (PDT) MIME-Version: 1.0 In-Reply-To: References: From: Ian Kelly Date: Thu, 25 Jul 2013 22:02:18 -0600 Subject: Re: How would I do this? To: Python Content-Type: text/plain; charset=ISO-8859-1 X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.15 Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Newsgroups: comp.lang.python Message-ID: Lines: 18 NNTP-Posting-Host: 2001:888:2000:d::a6 X-Trace: 1374811387 news.xs4all.nl 15916 [2001:888:2000:d::a6]:55290 X-Complaints-To: abuse@xs4all.nl Xref: csiph.com comp.lang.python:51280 On Thu, Jul 25, 2013 at 9:40 PM, wrote: > Thank you for the quick reply. Unfortunately I'm still a little confused... How might I implement that into my current code? Where you print spaces indicating an empty space, you need to look up the current square in the board data structure to see what is contained there (whether it's an empty space or not) and print it accordingly. I strongly recommend that you work out how to print the board using nested for loops instead of all those individual print statements. The result will be more compact, easier to work with, and less error-prone. The basic skeleton should look something like this: for row in range(8): for column in range(8): print(board[row][column]) Which you'll need to embellish with the row and column dividers and labels.