Path: csiph.com!newsfeed.hal-mli.net!feeder3.hal-mli.net!newsfeed.hal-mli.net!feeder1.hal-mli.net!newsfeed.xs4all.nl!newsfeed3.news.xs4all.nl!xs4all!newsgate.cistron.nl!newsgate.news.xs4all.nl!post.news.xs4all.nl!not-for-mail Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.000 X-Spam-Evidence: '*H*': 1.00; '*S*': 0.00; 'essentially': 0.04; 'exercise': 0.04; 'subject:help': 0.08; 'bash': 0.09; 'lookup': 0.09; 'method,': 0.09; 'received:80.91': 0.09; 'received:80.91.229': 0.09; 'received:gmane.org': 0.09; 'received:list': 0.09; 'subject:into': 0.09; 'url:github': 0.09; 'python': 0.11; 'question.': 0.14; '(1,': 0.16; '(2,': 0.16; '(8,': 0.16; '16)': 0.16; '31.': 0.16; 'hashed': 0.16; 'length)': 0.16; 'length,': 0.16; 'magic': 0.16; 'received:80.91.229.3': 0.16; 'received:dip0.t-ipconnect.de': 0.16; 'received:plane.gmane.org': 0.16; 'received:t-ipconnect.de': 0.16; 'selects': 0.16; 'seperate': 0.16; 'tuple': 0.16; 'two,': 0.16; 'wrote:': 0.18; 'code.': 0.18; 'do.': 0.18; 'library': 0.18; 'trying': 0.19; 'pointed': 0.19; 'split': 0.19; 'command': 0.22; 'header:User-Agent:1': 0.23; 'string,': 0.24; 'script': 0.25; 'values': 0.27; 'header:X-Complaints-To:1': 0.27; 'function': 0.29; 'wondering': 0.29; 'subject:list': 0.30; 'skip:( 20': 0.30; 'code': 0.31; 'lines': 0.31; '"",': 0.31; 'assert': 0.31; 'extract': 0.31; 'keys': 0.31; 'option.': 0.31; 'tuples': 0.31; 'url:python': 0.33; 'could': 0.34; 'knowledge': 0.35; 'subject:with': 0.35; 'skip:s 30': 0.35; 'something': 0.35; 'one,': 0.35; 'google': 0.35; 'there': 0.35; 'located': 0.36; 'url:org': 0.36; 'should': 0.36; 'two': 0.37; 'list': 0.37; 'list.': 0.37; 'to:addr:python-list': 0.38; 'list,': 0.38; 'anything': 0.39; 'expect': 0.39; 'to:addr:python.org': 0.39; 'skip:p 20': 0.39; 'received:org': 0.40; 'how': 0.40; 'skip:u 10': 0.60; 'read': 0.60; 'improved': 0.60; 'results.': 0.60; 'new': 0.61; 'first': 0.61; 'making': 0.63; 'such': 0.63; 'happen': 0.63; 'decided': 0.64; 'more': 0.64; 'here': 0.66; 'lack': 0.78; 'email name:peter': 0.84; 'do:': 0.91 X-Injected-Via-Gmane: http://gmane.org/ To: python-list@python.org From: Peter Otten <__peter__@web.de> Subject: Re: help with explaining how to split a list of tuples into parts Date: Sat, 13 Jul 2013 09:28:50 +0200 Organization: None References: Mime-Version: 1.0 Content-Type: text/plain; charset="ISO-8859-1" Content-Transfer-Encoding: 7Bit X-Gmane-NNTP-Posting-Host: p5084b367.dip0.t-ipconnect.de User-Agent: KNode/4.7.3 X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.15 Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Newsgroups: comp.lang.python Message-ID: Lines: 79 NNTP-Posting-Host: 2001:888:2000:d::a6 X-Trace: 1373700539 news.xs4all.nl 15871 [2001:888:2000:d::a6]:45876 X-Complaints-To: abuse@xs4all.nl Xref: csiph.com comp.lang.python:50580 peter@ifoley.id.au wrote: > Hi List, > > I am new to Python and wondering if there is a better python way to do > something. As a learning exercise I decided to create a python bash > script to wrap around the Python Crypt library (Version 2.7). > > My attempt is located here - https://gist.github.com/pjfoley/5989653 > > I am trying to wrap my head around list comprehensions, I have read the > docs at > http://docs.python.org/2/tutorial/datastructures.html#list-comprehensions > and read various google results. I think my lack of knowledge is making > it difficult to know what key word to search on. > > Essentially I have this list of tuples > > # Tuple == (Hash Method, Salt Length, Magic String, Hashed Password > # Length) > supported_hashes=[('crypt',2,'',13), ('md5',8,'$1$',22), > ('sha256',16,'$5$',43), ('sha512',16,'$6$',86)] > > This list contains the valid hash methods that the Crypt Library supports > plus some lookup values I want to use in the code. > > I have managed to work out how to extract a list of just the first value > of each tuple (line 16) which I use as part of the validation against the > --hash argparse option. > > My Question. > > Looking at line 27, This line returns the tuple that mataches the hash > type the user selects from the command line. Which I then split the > seperate parts over lines 29 to 31. > > I am wondering if there is a more efficient way to do this such that I > could do: > > salt_length, hash_type, expected_password_length = [x for x in > supported_hashes if x[0] == args.hash] > > From my limited understanding the first x is the return value from the > function which meets the criteria. So could I do something like: > > ... = [(x[0][1], x[0][2], x[0][3]) for x in supported_hashes if x[0] == > args.hash] > > I am happy to be pointed to some documentation which might help clarify > what I need to do. > > Also if there is anything else that could be improved on with the code > happy to be contacted off list. Every time when you have to look up something you should think 'dict', and I expect that pretty that will happen automatically. Also, to split a tuple into its items you can "unpack" it: triple = (1, 2, 3) one, two, three = triple assert one == 1 and two == 2 and three == 3 So: supported_hashes = { "crypt": (2, "", 13), "md5": (8, "$1$", 22), ... } ... parser.add_argument( '--hash', default='sha512', choices=supported_hashes, # accept the keys help='Which Hash function to use') ... salt_length, hash_type, expected_password_length = supported_hashes[args.hash] ...