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Date: Tue, 4 Dec 2012 14:55:44 +0400
Subject: scope, function, mutable
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Hi,

What is the appropriate definition for the following behavior in Python 2.7
(see code below).
Both functions have assignment in it (like "x = ") so I assume, that x is a
local variable in both functions.
Also I thought this rule doesn't depend on WHERE in this function we find
the assignment.

But in both functions x becomes local variable only AFTER assignment, so in
f2 x[1] = 99 changes the global varialble (btw, x[3] = 99 doesn't).

def f1(x):
    x = [44] + x[1:]
    x[1] = 99

def f2(x):
    x[1] = 99
    x = [44] + x[1:]
    x[3] = 99

t = [1,2,3,4,5,6,7]
f1(t)
print t                            # [1, 2, 3, 4, 5, 6, 7]
t = [1,2,3,4,5,6,7]
f2(t)
print t                            # [1, 99, 3, 4, 5, 6, 7]

Thank you.

Roman Gusarev.

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Hi,<div><br></div><div>What is the appropriate definition for the following=
 behavior in Python 2.7 (see code below).</div><div>Both functions have ass=
ignment in it (like &quot;x =3D &quot;) so I assume, that x is a local vari=
able in both functions.</div>
<div>Also I thought this rule doesn&#39;t depend on WHERE in this function =
we find the assignment.</div><div><br></div><div>But in both functions x be=
comes local variable only AFTER assignment, so in f2 x[1] =3D 99 changes th=
e global varialble (btw, x[3] =3D 99 doesn&#39;t).</div>
<div><br></div><div><div>def f1(x):</div><div>=A0 =A0 x =3D [44] + x[1:]</d=
iv><div>=A0 =A0 x[1] =3D 99</div><div><br></div><div>def f2(x):</div><div>=
=A0 =A0 x[1] =3D 99</div><div>=A0 =A0 x =3D [44] + x[1:]</div><div>=A0 =A0 =
x[3] =3D 99</div><div><br></div>
</div><div><div>t =3D [1,2,3,4,5,6,7]</div><div>f1(t)</div><div>print t =A0=
 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0#=A0[1, 2, 3, 4, 5, 6, =
7]</div><div>t =3D [1,2,3,4,5,6,7]</div><div>f2(t)</div><div>print t=A0=A0 =
=A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0#=A0[1, 99, 3, 4, 5, 6, =
7]</div>
</div><div><br></div><div>Thank you.</div><div><br></div><div>Roman Gusarev=
.</div>

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