Path: csiph.com!fu-berlin.de!uni-berlin.de!not-for-mail From: jmp Newsgroups: comp.lang.python Subject: Re: Summary grid Date: Wed, 22 Jun 2016 18:20:37 +0200 Lines: 56 Message-ID: References: Mime-Version: 1.0 Content-Type: text/plain; charset=windows-1252; format=flowed Content-Transfer-Encoding: 7bit X-Trace: news.uni-berlin.de A/gUu92wll0pAXRF2EwF/Ajqr+KRT5MptzQkL7+Gd7Ng== Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.000 X-Spam-Evidence: '*H*': 1.00; '*S*': 0.00; 'data:': 0.07; '[1,': 0.09; 'builtins': 0.09; 'grid': 0.09; 'received:80.91': 0.09; 'received:80.91.229': 0.09; 'received:gmane.org': 0.09; 'received:list': 0.09; 'rows': 0.09; 'python': 0.10; '"d",': 0.16; '"zip"': 0.16; '0],': 0.16; '[2,': 0.16; 'categories,': 0.16; 'duplicates': 0.16; 'magic': 0.16; 'received:80.91.229.3': 0.16; 'received:io': 0.16; 'received:plane.gmane.org': 0.16; 'received:psf.io': 0.16; 'subject:Summary': 0.16; 'wrote:': 0.16; 'function:': 0.22; 'cheers,': 0.22; 'header:In-Reply-To:1': 0.24; 'header:User-Agent:1': 0.26; 'example': 0.26; 'header:X -Complaints-To:1': 0.26; 'entered': 0.27; 'function': 0.28; 'cat': 0.29; 'summary': 0.29; 'print': 0.30; 'code': 0.30; 'this?': 0.34; 'list': 0.34; 'could': 0.35; 'done': 0.35; 'item': 0.35; 'to:addr :python-list': 0.36; 'pm,': 0.36; 'subject:: ': 0.37; 'really': 0.37; 'say': 0.37; 'thanks': 0.37; 'received:org': 0.37; 'skip:z 10': 0.38; 'data': 0.39; 'easily': 0.39; 'to:addr:python.org': 0.40; 'care': 0.60; 'received:194': 0.61; 'charset:windows-1252': 0.62; 'results': 0.66; 'worth': 0.67 X-Injected-Via-Gmane: http://gmane.org/ X-Gmane-NNTP-Posting-Host: paris.sequans.com User-Agent: Mozilla/5.0 (X11; Linux x86_64; rv:31.0) Gecko/20100101 Thunderbird/31.6.0 In-Reply-To: X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.22 Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , X-Mailman-Original-Message-ID: X-Mailman-Original-References: Xref: csiph.com comp.lang.python:110325 On 06/22/2016 04:46 PM, Jignesh Sutar wrote: > Say I have list of data as given in the example code below, I want to find > all the unique categories (alphabetic letters) and unique IDs (numbers) and > then produce a summary grid as manually entered in the "results". How could > I code this? > > Many thanks in advance, > Jignesh > > > data= ["A.1", "A.2", "A.3", "B.1", "C.2", "C.3", "D.4", "E.5", "E.6"] > > cols=[] > rows=[] > for item in data: > i=item.split(".") > if i[0] not in cols: cols.append(i[0]) > if i[1] not in rows: rows.append(i[1]) > > print cols > print rows > > results= > [["Row/Col", "A", "B", "C", "D", "E"], > [1, 1, 1, 0, 0, 0], > [2, 1, 0, 1, 0, 0], > [3, 1, 0, 1, 0, 0], > [4, 0, 0, 0, 1, 0], > [5, 0, 0, 0, 0, 1], > [6, 0, 0, 0, 0, 1]] > Easily done using only builtins and list comprehension: data= ["A.1", "A.2", "A.3", "B.1", "C.2", "C.3", "D.4", "E.5", "E.6"] # python magic with the "zip" function # "set" will take care of removing duplicates categories, ids = map(set, zip(*[d.split('.') for d in data])) results = [] for id_ in sorted(map(int,ids)): results.append([data.count("%s.%d" % (cat, id_)) for cat in sorted(categories)]) print results If you don't really understand the zip function: http://nedbatchelder.com/text/iter.html The whole presentation is worth reading. Cheers, Jm