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From: Mark Lawrence <breamoreboy@yahoo.co.uk>
Subject: Re: How to do this?
Date: Mon, 01 Apr 2013 13:28:51 +0100
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Xref: csiph.com comp.lang.python:42461

On 01/04/2013 11:14, Ana Dionísio wrote:
> So I have this script:
>
> "
> from numpy import array

Are you aware that this overrides the Python builtin array?  It's 
usually but not always better to do this

import numpy as np
vt = np.array(vt, dtype=dict)

>
> vt=[0]*20
> vt = array(vt, dtype=dict)
>
> for t in range(20):
>      if t == 4:
>          vt[t]=1
>
>      else:
>          vt[t]=0

Why the loop, you've already initialise the array to zeroes?

> "
>
> And have this output:
>
> [0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0]
>
> What I need is when t == 4 I need to put 1 in that position and in the next 3, for example the following output:
>
> [0 0 0 0 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0]
>
> Do you have any suggestions?

Use slicing.
vt[4:8] = 1

>
>
> I'm sorry if I can't explain this in a better way, English is not my first language
>
> Thank you
>

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Mark Lawrence