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Subject: Re: Creating a dictionary from a .txt file
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Xref: csiph.com comp.lang.python:42384

On Sunday, March 31, 2013 12:06:18 PM UTC-4, Chris Angelico wrote:
> On Mon, Apr 1, 2013 at 2:52 AM, C.T.
> 
> > After playing around with the code, I came up with the following code to get everything into a list:
> 
> >
> 
> > d=[]
> 
> > car_file = open('worstcars.txt', 'r')
> 
> > for line in car_file:
> 
> >     d.append(line.strip('\n'))
> 
> > print (d)
> 
> > car_file.close()
> 
> >
> 
> > Every line is now an element in list d. The question I have now is how can I make a dictionary out of the list d with the car manufacturer as the key and a tuple containing the year and the model should be the key's value.
> 
> 
> 
> Ah, a nice straight-forward text parsing problem!
> 
> 
> 
> The question is how to recognize the manufacturer. Is it guaranteed to
> 
> be the second blank-delimited word, with the year being the first? If
> 
> so, you were almost there with .split().
> 
> 
> 
> car_file = open('worstcars.txt', 'r')
> 
> # You may want to consider the 'with' statement here - no need to close()
> 
> for line in car_file:
> 
>     temp = line.split(None, 2)
> 
>     if len(temp)==3:
> 
>         year, mfg, model = temp
> 
>         # Now do something with these three values
> 
>         print("Manufacturer: %s  Year: %s  Model: %s"%(mfg,year,model))
> 
> 
> 
> That's sorted out the parsing side of things. Do you know how to build
> 
> up the dictionary from there?
> 
> 
> 
> What happens if there are multiple entries in the file for the same
> 
> manufacturer? Do you need to handle that?
> 
> 
> 
> ChrisA

Thank you, Chris! I could use slicing and indexing to build the dictionary but the problem is with the car manufacturer an the car model. Either or both could be multiple names.