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Newsgroups: comp.lang.python
Date: Sun, 31 Mar 2013 09:52:50 -0700 (PDT)
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Subject: Re: Creating a dictionary from a .txt file
From: "C.T." <swilks06@gmail.com>
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On Sunday, March 31, 2013 12:20:25 PM UTC-4, zipher wrote:
> Every line is now an element in list d. The question I have now is how ca=
n I make a dictionary out of the list d with the car manufacturer as the ke=
y and a tuple containing the year and the model should be the key's value. =
Here is a sample of what list d looks like:
>=20
>=20
>=20
>=20
> ['1899 Horsey Horseless', '1909 Ford Model T', '1911 Overland OctoAuto', =
'2003 Hummer H2', '2004 Chevy SSR']
>=20
>=20
>=20
> Any help would be appreciated!
>=20
>=20
>=20
>=20
> As long as your data is consistently ordered, just use list indexing. =A0=
d[2] is your key, and (d[1],d[3]) the key's value.
>=20
>=20
>=20
> Mark
> Tacoma, Washington


Thank you, Mark! My problem is the data isn't consistently ordered. I can u=
se slicing and indexing to put the year into a tuple, but because a car man=
ufacturer could have two names (ie, Aston Martin) or a car model could have=
 two names(ie, Iron Duke), its harder to use slicing and indexing for those=
 two.  I've added the following, but the output is still not what I need it=
 to be.


t=3D{}
for i in d :
    t[d[d.index(i)][5:]]=3D tuple(d[d.index(i)][:4])

print (t)

The output looks something like this:

{'Ford Model T': ('1', '9', '0', '9'), 'Mosler Consulier GTP': ('1', '9', '=
8', '5'), 'Scripps-Booth Bi-Autogo': ('1', '9', '1', '3'), 'Morgan Plus 8 P=
ropane': ('1', '9', '7', '5'), 'Fiat Multipla': ('1', '9', '9', '8'), 'Ford=
 Pinto': ('1', '9', '7', '1'), 'Triumph Stag': ('1', '9', '7', '0'), 'BMW 7=
-series': ('2', '0', '0', '2')}


Here the key is the car manufacturer and car model and the value is a tuple=
 containing the year separated by a comma.( Not sure why that is ?)