Path: csiph.com!fu-berlin.de!uni-berlin.de!not-for-mail From: Chris Kaynor Newsgroups: comp.lang.python Subject: Re: breaking out of outer loops Date: Mon, 7 Mar 2016 15:42:48 -0800 Lines: 69 Message-ID: References: Mime-Version: 1.0 Content-Type: text/plain; charset=UTF-8 X-Trace: news.uni-berlin.de KrJdxcDHCUajIP1xIahDLAjeG8wMHoWBAXoqr92lQUhg== Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.001 X-Spam-Evidence: '*H*': 1.00; '*S*': 0.00; 'lines,': 0.05; 'line:': 0.07; 'stops': 0.07; 'exiting': 0.09; 'files:': 0.09; 'bug': 0.10; 'example:': 0.10; 'python': 0.10; 'python.': 0.11; 'exception': 0.13; 'files.': 0.13; 'def': 0.13; 'file,': 0.15; '2016': 0.16; 'email addr:hotmail.com>': 0.16; 'line.split()': 0.16; 'loops': 0.16; 'received:io': 0.16; 'received:psf.io': 0.16; 'rough': 0.16; 'subject:breaking': 0.16; 'wrote:': 0.16; 'nested': 0.18; 'try:': 0.18; '>>>': 0.20; 'to:name:python-list@python.org': 0.20; 'file:': 0.22; 'function,': 0.22; 'function:': 0.22; 'trying': 0.22; 'code,': 0.23; 'bit': 0.23; 'header:In-Reply-To:1': 0.24; 'mon,': 0.24; 'error': 0.27; 'message-id:@mail.gmail.com': 0.27; 'raise': 0.29; "i'm": 0.30; 'print': 0.30; 'code': 0.30; 'mention': 0.30; 'probably': 0.31; "can't": 0.32; 'especially': 0.32; 'class': 0.33; 'errors,': 0.33; 'raising': 0.33; 'traceback': 0.33; 'structure': 0.34; 'file': 0.34; 'except': 0.34; 'list': 0.34; 'received:google.com': 0.35; 'could': 0.35; 'label': 0.35; 'something': 0.35; 'but': 0.36; 'skip:i 20': 0.36; 'should': 0.36; 'there': 0.36; 'received:209.85': 0.36; 'possible': 0.36; 'skip:{ 10': 0.36; 'to:addr:python-list': 0.36; 'pm,': 0.36; 'subject:: ': 0.37; 'missing': 0.37; 'received:209.85.213': 0.37; 'manual': 0.38; 'no,': 0.38; 'received:209': 0.38; 'skip:p 20': 0.38; 'does': 0.39; 'to:addr:python.org': 0.40; 'some': 0.40; 'your': 0.60; 'entire': 0.61; 'details': 0.62; 'more': 0.63; 'due': 0.65; 'mar': 0.65; 'apart': 0.70; 'approach.': 0.91 DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=zindagigames-com.20150623.gappssmtp.com; s=20150623; h=mime-version:in-reply-to:references:from:date:message-id:subject:to; bh=d4RM7NW5iN0Ghb+0LCbCeRVBNOUAifxxn1tKJ5oIWlo=; b=ks06w6T1dGaX+hkVDNPUEqPpOvRWTEVA/Nibsu095sdmVsZozZrT+IeVzgdstvsCUt pFC++OcJ5FGnOHdWwLs19hSkXvCUJykjTCVE8EGjjeFnOUAuN7CJKCZTVJGfavHALmxU a6R2lB1M4H76PmT4tJsYAnuRZi1ILaPfCJZ70rBPW6fNxPe6CBftPt9uIYtIzjjRIXXe 1N0bbqXcq2BiFj5yEym74yp1sBBgwwZl56P2BAZaMXV8KZQMil2lI24I3hf3oiCwlB/t cQKCZ7pS89lFWdAIq1P5tN4+24MtFDNLEkDGYJ0OhnAqRMvWIAc0Qu8zp6m0vKzidyeU 8HLw== X-Google-DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=1e100.net; s=20130820; h=x-gm-message-state:mime-version:in-reply-to:references:from:date :message-id:subject:to; bh=d4RM7NW5iN0Ghb+0LCbCeRVBNOUAifxxn1tKJ5oIWlo=; b=LywS10d1NoF+PdJMMo65nk0Ma2uj0FI0Y08KXhruLNKWfepuRlPCCbXEAhqUeYPUeR 4CQb9Qa/bzqtOGOPL7LhTPiASfKkK+mltIjeYrfNymLw1bvBTjND/7NQSQwa6Ow1OQI4 9Fas9+TdBP8opbDLA6xtHp1/nMyMKdGoyzJBqNWRglSpbkty188ZwAxJ+yxL298U1ixe 1+eGvZvhynYOU+7xwIAZO/PAOEX/lxidYXIF9aQQSFZRgR9HrFzs2Mm4tiRChbz/J/x5 hZtP0HhqGZmqidHBzXUz4GJ+QnJbeR0Gh+lepfnfbH52AB8SE19CzQKt3FuRopOCg24V cTOA== X-Gm-Message-State: AD7BkJI8lieM/G+UHYB0NTx429i4zvL6L7hYLmlOO8Mnvx93atjI7uVq1VeAyAj26/vAV4nur/OorNR0Woc5yw== X-Received: by 10.31.6.17 with SMTP id 17mr23439045vkg.75.1457394188179; Mon, 07 Mar 2016 15:43:08 -0800 (PST) In-Reply-To: X-Content-Filtered-By: Mailman/MimeDel 2.1.21 X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.21 Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Xref: csiph.com comp.lang.python:104274 On Mon, Mar 7, 2016 at 3:21 PM, Fillmore wrote: > On 3/7/2016 6:17 PM, Ian Kelly wrote: > >> On Mon, Mar 7, 2016 at 4:09 PM, Fillmore >> wrote: >> >>> >>> I must be missing something simple because I can't find a way to break >>> out >>> of a nested loop in Python. >>> >>> Is there a way to label loops? >>> >> >> No, you can't break out of nested loops, >> > > wow...this is a bit of a WTF moment to me :( > > apart from structuring your >> code such that return does what you want. >> >> > Can you elaborate? apologies, but I'm new to python and trying to find my > way out of perl.... The normal way of breaking out of some set of loops would be to structure your code so that you have a function, and when you want to break out of some of multiple loops, you can just call return. As a very rough example: def processFile(file): for line in file: section = line.split() for section in line: if sectionCorrupt: return # Stops processing the entire file, by exiting the function, but keeps processing the list of files. for file in files: processFile(file) Alternatively, as you mention corrupted lines, perhaps raising an exception would be the best approach. And the same rough example, using an exception without a function: for file in files: try: for line in file: section = line.split() for section in line: if sectionCorrupt: raise Exception('Section corrupt') # You probably want more details here, for possible manual repair. You could also have a custom exception class for more control. except Exception as e: print('Failed to process the file {} with error {}.'.format(file, str(e))) # Probably should also print the entire traceback to aid in repairing errors, especially if they are due to a bug in the code, but this is the rough idea.