Path: csiph.com!usenet.pasdenom.info!news.etla.org!news.stack.nl!newsfeed.xs4all.nl!newsfeed4.news.xs4all.nl!xs4all!post.news.xs4all.nl!not-for-mail Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.021 X-Spam-Evidence: '*H*': 0.96; '*S*': 0.00; 'example:': 0.03; '"if': 0.09; 'function,': 0.09; 'subject:number': 0.09; 'subject:Help': 0.11; 'def': 0.12; 'be:': 0.16; 'behaviour.': 0.16; 'division.': 0.16; 'from:addr:rosuav': 0.16; 'from:name:chris angelico': 0.16; 'infinitely': 0.16; 'left,': 0.16; 'numbers;': 0.16; 'wrote:': 0.18; '>>>': 0.22; 'print': 0.22; 'integer': 0.24; 'sorry,': 0.24; 'fine': 0.24; '(or': 0.24; 'define': 0.26; 'header:In-Reply-To:1': 0.27; 'am,': 0.29; "doesn't": 0.30; 'message-id:@mail.gmail.com': 0.30; 'that.': 0.31; 'division': 0.31; 'prints': 0.31; 'writes:': 0.31; 'fri,': 0.33; 'subject:the': 0.34; 'received:209.85': 0.35; 'received:google.com': 0.35; 'there': 0.35; 'false': 0.36; 'should': 0.36; 'positive': 0.37; 'received:209': 0.37; 'handle': 0.38; 'to:addr:python-list': 0.38; 'to:addr:python.org': 0.39; 'called': 0.40; 'eventually': 0.60; 'negative': 0.60; 'removing': 0.60; 'numbers': 0.61; 'email addr:gmail.com': 0.63; 'due': 0.66; 'mar': 0.68; 'special': 0.74; 'subject:printing': 0.84; 'continue.': 0.91; 'thing,': 0.91; '2013': 0.98 DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=gmail.com; s=20120113; h=mime-version:x-received:in-reply-to:references:date:message-id :subject:from:to:content-type; bh=f7pmrw2HzIjDhQzYsHQOJYoq5/GyMmr9GdYgrRHJqvI=; b=iq+yWeNyv0lVEWiazyQel/vC91X2bYVs90BFJES+zcaL7Oipnsr1Ade4Gvx0a/CjHJ agiB0yrYpevqj9Ha0GLp5u7LA/QtKUiSLweYCNkzqs147GghZno2k3p7rEJzHuLcHeCp ksRb4T6xQDY86F/EB1Nmmo+I8K0kcwi/GDKNGkMKPh4d7kg9IyiEO4ei5K/9ELkvCiyA 30FC9g8mOzWO5v7w5wp250ERn62345rKCRrS11wDCaLnJWEBW5kQUIN531kfhtu3E7tc UbpNkYoOUw3U67WTv6GCoKEXnVSuzWFiOKKdbJJNyJL2VidilzlGD4l6kWoUg7yaaQi5 jq9A== MIME-Version: 1.0 X-Received: by 10.52.16.211 with SMTP id i19mr6985487vdd.91.1364491179960; Thu, 28 Mar 2013 10:19:39 -0700 (PDT) In-Reply-To: References: <7764e61c-e4cc-413a-a76d-2d37f39abc61@googlegroups.com> Date: Fri, 29 Mar 2013 04:19:39 +1100 Subject: Re: Help printing the integers of a longer number From: Chris Angelico To: python-list@python.org Content-Type: text/plain; charset=ISO-8859-1 X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.15 Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Newsgroups: comp.lang.python Message-ID: Lines: 60 NNTP-Posting-Host: 2001:888:2000:d::a6 X-Trace: 1364491182 news.xs4all.nl 6844 [2001:888:2000:d::a6]:60485 X-Complaints-To: abuse@xs4all.nl Xref: csiph.com comp.lang.python:42173 On Fri, Mar 29, 2013 at 4:11 AM, Jussi Piitulainen wrote: > Jussi Piitulainen writes: > >> khaosyt@gmail.com writes: >> >> > I want to print the individual numbers of a large number using >> > division and modulus division. >> > >> > For example: >> > >> > Enter a positive integer: 54321 >> > 5 >> > 4 >> > 3 >> > 2 >> > 1 >> >> Those numbers are called the digits of the large number. >> >> With divmod(54321, 10) you get both the number that is "left" after >> removing the last digit, and the last digit: >> >> >>> left, last = divmod(54321, 10) >> >>> left >> 5432 >> >>> last >> 1 >> >> Define a function, print_digits(num), that prints the digits of the >> non-negative integer num. Zero turns out fine so let's allow zero: >> >> def print_digits(num): >> left, last = divmod(num, 10) >> if left < 0: print the digits of left >> print(last) > > Blush. That should be: > > ... > if left > 0: ... > ... > > (Or just "if left" because left will eventually be 0, positive numbers > are true values, and 0 is a false value.) > > Sorry about that. Sorry, I just nitpicked that very thing, hehe :) Note that this doesn't work with negative numbers; it'll infinitely recurse, due to divmod's behaviour. You'd need a special trap in there to handle that: if num<0: print("-") num=-num # and continue. ChrisA