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Subject: Re: Check if a given value is out of certain range
From: Michiel Overtoom <motoom@xs4all.nl>
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Date: Mon, 5 Oct 2015 10:18:29 +0200
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Xref: csiph.com comp.lang.python:97401


Why not use a function?


    if outside(x, 0, 10):
        print("x has wrong value")
    else:
        print("x has good value")


where 'outside' is defined as:

    def outside(value, lowerbound, upperbound):
        return value < lowerbound or value > upperbound  

Greetings,