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Date: Sat, 3 Mar 2012 21:48:58 -0800
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Subject: Re: The original command python line
From: Chris Rebert <clp2@rebertia.com>
To: Damjan Georgievski <gdamjan@gmail.com>
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On Sat, Mar 3, 2012 at 9:38 PM, Damjan Georgievski <gdamjan@gmail.com> wrot=
e:
> How can I get the *really* original command line that started my python
> interpreter?
>
> Werkzeug has a WSGI server which reloads itself when files are changed
> on disk. It uses `args =3D [sys.executable] + sys.argv` to kind of
> recreate the command line, and the uses subprocess.call to run that
> command line.
>
> BUT that's problematic as, when you run::
>
> =C2=A0 =C2=A0 =C2=A0 =C2=A0python -m mypackage --config
>
> sys.argv printed in mypackage/__main__.py will be::
>
> =C2=A0 =C2=A0 =C2=A0 =C2=A0['/full/path/to/mypackage/__main__.py', '--con=
fig']
>
> so you get::
>
> =C2=A0 =C2=A0 =C2=A0 =C2=A0python /full/path/to/mypackage/__main__.py --c=
onfig
>
> instead of::
>
> =C2=A0 =C2=A0 =C2=A0 =C2=A0python -m mypackage --config
>
>
> the difference in the 2 cases is what the current package is, and
> whether you can use relative imports.

On Linux, you can read from:
    /proc/<PID here>/cmdline
to get the null-delimited "command line".

Sidenote: Consensus generally seems to be that relative imports are a bad i=
dea.

Cheers,
Chris