Path: csiph.com!usenet.pasdenom.info!weretis.net!feeder4.news.weretis.net!ecngs!feeder2.ecngs.de!newsfeed.freenet.ag!news2.euro.net!newsgate.cistron.nl!newsgate.news.xs4all.nl!post.news.xs4all.nl!not-for-mail
Newsgroups: comp.lang.python
Date: Thu, 6 Sep 2012 13:26:32 -0700 (PDT)
In-Reply-To: <mailman.309.1346944827.27098.python-list@python.org>
Complaints-To: groups-abuse@google.com
Injection-Info: glegroupsg2000goo.googlegroups.com; posting-host=81.166.233.176; posting-account=04fc6goAAACDYxuhiIAKatXLjxcOghf2
References: <feae1d5a-c477-4e21-8136-c14e38672cb9@googlegroups.com> <mailman.309.1346944827.27098.python-list@python.org>
User-Agent: G2/1.0
MIME-Version: 1.0
Subject: Re: Function for examine content of directory
From: Tigerstyle <laddosingh@gmail.com>
To: comp.lang.python@googlegroups.com
Content-Type: text/plain; charset=ISO-8859-1
Content-Transfer-Encoding: quoted-printable
Cc: python-list@python.org
Precedence: list
Message-ID: <mailman.326.1346963199.27098.python-list@python.org>
Lines: 122
NNTP-Posting-Host: 2001:888:2000:d::a6
Xref: csiph.com comp.lang.python:28637

Thanks, just what I was looking for :-)

T

kl. 17:20:27 UTC+2 torsdag 6. september 2012 skrev MRAB f=F8lgende:
> On 06/09/2012 15:56, Tigerstyle wrote:
>=20
> > Hi guys,
>=20
> >
>=20
> > I'm trying to write a module containing a function to examine the conte=
nts of the current working directory and print out a count of how many file=
s have each extension (".txt", ".doc", etc.)
>=20
> >
>=20
> > This is the code so far:
>=20
> > --
>=20
> > import os
>=20
> >
>=20
> > path =3D "v:\\workspace\\Python2_Homework03\\src\\"
>=20
> > dirs =3D os.listdir( path )
>=20
> > filenames =3D {"this.txt", "that.txt", "the_other.txt","this.doc","that=
.doc","this.pdf","first.txt","that.pdf"}
>=20
> > extensions =3D []
>=20
> > for filename in filenames:
>=20
> >      f =3D open(filename, "w")
>=20
> >      f.write("Some text\n")
>=20
> >      f.close()
>=20
> >      name , ext =3D os.path.splitext(f.name)
>=20
> >      extensions.append(ext)
>=20
> >
>=20
> > # This would print all the files and directories
>=20
> > for file in dirs:
>=20
> >      print(file)
>=20
> >
>=20
> > for ext in extensions:
>=20
> >      print("Count for %s: " %ext, extensions.count(ext))
>=20
> >
>=20
> > --
>=20
> >
>=20
> > When I'm trying to get the module to print how many files each extensio=
n has, it prints the count of each ext multiple times for each extension ty=
pe. Like this:
>=20
> >
>=20
> > this.pdf
>=20
> > the_other.txt
>=20
> > this.doc
>=20
> > that.txt
>=20
> > this.txt
>=20
> > that.pdf
>=20
> > first.txt
>=20
> > that.doc
>=20
> > Count for .pdf:  2
>=20
> > Count for .txt:  4
>=20
> > Count for .doc:  2
>=20
> > Count for .txt:  4
>=20
> > Count for .txt:  4
>=20
> > Count for .pdf:  2
>=20
> > Count for .txt:  4
>=20
> > Count for .doc:  2
>=20
> >
>=20
> That's because each extension can occur multiple times in the list.
>=20
>=20
>=20
> Try the Counter class:
>=20
>=20
>=20
> from collections import Counter
>=20
>=20
>=20
> for ext, count in Counter(extensions).items():
>=20
>      print("Count for %s: " % ext, count)