Path: csiph.com!usenet.pasdenom.info!dedibox.gegeweb.org!gegeweb.eu!nntpfeed.proxad.net!proxad.net!feeder1-2.proxad.net!news.tele.dk!news.tele.dk!small.news.tele.dk!newsgate.cistron.nl!newsgate.news.xs4all.nl!post.news.xs4all.nl!not-for-mail Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.025 X-Spam-Evidence: '*H*': 0.95; '*S*': 0.00; 'detect': 0.07; 'socket': 0.07; 'subject:same': 0.07; 'yeah,': 0.09; 'subject:How': 0.10; 'random': 0.14; "'localhost',": 0.16; 'filesystem': 0.16; 'from:addr:rosuav': 0.16; 'from:name:chris angelico': 0.16; 'hint': 0.16; 'wrote:': 0.18; 'wed,': 0.18; 'file,': 0.19; 'otherwise,': 0.22; 'comparing': 0.24; 'recognize': 0.24; 'initial': 0.24; 'file.': 0.24; 'possibly': 0.26; 'header:In- Reply-To:1': 0.27; 'am,': 0.29; 'message-id:@mail.gmail.com': 0.30; "skip:' 10": 0.31; 'run': 0.32; '(i.e.': 0.33; 'guess': 0.33; 'subject:the': 0.34; 'could': 0.34; 'connection': 0.35; 'created': 0.35; 'received:google.com': 0.35; 'thanks': 0.36; 'server': 0.38; 'nov': 0.38; 'to:addr:python-list': 0.38; 'files': 0.38; 'to:addr:python.org': 0.39; 'either': 0.39; 'tell': 0.60; 'course': 0.61; 'name': 0.63; 'taking': 0.65; 'connection.': 0.74; 'hoping': 0.75; '127.0.0.1': 0.84; '4:26': 0.84; 'generation.': 0.91; '2013': 0.98 DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=gmail.com; s=20120113; h=mime-version:in-reply-to:references:date:message-id:subject:from:to :content-type; bh=NnTYiuyf193iIRhXEvbtAYcLMka+s50tOyy/KfZ3/ok=; b=uTo7RmE9R7uEh/p8zq1Ud786YU3zF0OLJCYHAeFzPbuzSMnlcTgvrwuZRltvYKrZIr dDALP0SdtQCQHn+h0hukicxTPl5WZ1zCIBUDfwcxKOwfrIGHH48EyfasAMPkgvA8BV5B RweMaN6YYd/ehiockEK1cQwdohL/B3D8RcDC8Tcwfn3dEtR8WLds4Wzy0lC3G8bh+IbW km3+n2NCOlLsJzPYFZhwxQKBy8tdAkrlK0PQQIxhNm/YFlhsrbkyVztYnt8+oaYBN5ke R2hTPRCjjZblhVxyBlVBp0Me5l9BXv6v47qdLT6Fk/5l/6e+ftZpKeAQ8nts+9M3onyc 5AEA== MIME-Version: 1.0 X-Received: by 10.67.23.71 with SMTP id hy7mr37525516pad.99.1385506573776; Tue, 26 Nov 2013 14:56:13 -0800 (PST) In-Reply-To: References: <7wfvqkrqvb.fsf@benfinney.id.au> Date: Wed, 27 Nov 2013 09:56:13 +1100 Subject: Re: How to determine whether client and server are on the same host From: Chris Angelico To: python-list@python.org Content-Type: text/plain; charset=ISO-8859-1 X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.15 Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Newsgroups: comp.lang.python Message-ID: Lines: 20 NNTP-Posting-Host: 2001:888:2000:d::a6 X-Trace: 1385506584 news.xs4all.nl 15869 [2001:888:2000:d::a6]:60429 X-Complaints-To: abuse@xs4all.nl Xref: csiph.com comp.lang.python:60545 On Wed, Nov 27, 2013 at 4:26 AM, Malte Forkel wrote: > Thanks for the explanation. I guess I was hoping that I could use some > property of a connection created with telnetlib or its socket to find > out whether it was actually a host-local connection (i.e. a connection > to 'localhost', '127.xx.xx.xx' or ''). > > So its either your initial suggestion of taking a hint from the user or > comparing files on the server and the client. You can still have a unique file, then; all you sacrifice is the random name generation. And you can of course recognize 127.x.y.z as local - it's just not the _only_ way to detect a local connection. Since this is, presumably, an optimization, you could possibly just tell people that it'll run faster if they tell it 127.0.0.1 than if they tell it {whatever other IPs the server has}. That may end up sufficient. Otherwise, yeah, detect by filesystem with a manually-created file. ChrisA