Path: csiph.com!v102.xanadu-bbs.net!xanadu-bbs.net!feeder.erje.net!eu.feeder.erje.net!newsfeed.xs4all.nl!newsfeed3.news.xs4all.nl!xs4all!news.tele.dk!news.tele.dk!small.news.tele.dk!newsgate.cistron.nl!newsgate.news.xs4all.nl!post.news.xs4all.nl!not-for-mail Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.162 X-Spam-Level: * X-Spam-Evidence: '*H*': 0.68; '*S*': 0.00; 'subject:Python': 0.06; 'assuming': 0.09; 'python': 0.11; 'url:download': 0.12; 'hashes': 0.16; 'md5': 0.16; 'operation.': 0.16; 'url:how': 0.16; ':-)': 0.16; 'wrote:': 0.18; 'value.': 0.19; '+0000': 0.22; 'to:name :python-list@python.org': 0.22; 'this?': 0.23; 'url:home': 0.24; 'mon,': 0.24; "i've": 0.25; 'script': 0.25; '>': 0.26; 'right.': 0.26; 'header:In-Reply-To:1': 0.27; "doesn't": 0.30; 'said,': 0.30; "i'm": 0.30; 'url:mailman': 0.30; 'program,': 0.31; 'code': 0.31; 'commonly': 0.31; 'steven': 0.31; 'them?': 0.31; 'anyone': 0.31; 'url:python': 0.33; 'date:': 0.34; 'subject:with': 0.35; 'tool': 0.35; 'but': 0.35; 'url:listinfo': 0.36; "i'll": 0.36; 'possible': 0.36; 'hi,': 0.36; 'url:org': 0.36; 'searching': 0.37; 'email addr:python.org': 0.37; 'project': 0.37; 'nov': 0.38; 'same.': 0.38; 'to:addr:python-list': 0.38; 'received:65.54': 0.38; 'received:65.54.190': 0.38; 'received:bay0.hotmail.com': 0.38; 'does': 0.39; 'subject:': 0.39; 'to:addr:python.org': 0.39; 'url:mail': 0.40; 'how': 0.40; 'skip:u 10': 0.60; 'course.': 0.60; 'most': 0.60; 'browser': 0.61; 'here:': 0.62; 'save': 0.62; 'address': 0.63; 'information': 0.63; 're:': 0.63; 'more': 0.64; 'school': 0.64; 'taking': 0.65; 'email name:python-list': 0.65; 'situation': 0.65; 'reverse': 0.68; 'collision': 0.84; 'email name:steve': 0.84; 'heh.': 0.84; 'technically': 0.84; 'browse': 0.95; '2013': 0.98 X-TMN: [aXBJXA1hzG7rWcWtypPn2p9ma1fOAfON] X-Originating-Email: [ycui@outlook.com] Content-Type: multipart/alternative; boundary="_b1dfdfa0-e1eb-462d-9d6f-a6538bf0af85_" From: Frank Cui To: "python-list@python.org" Subject: RE: Cracking hashes with Python Date: Mon, 25 Nov 2013 23:46:09 -0300 Importance: Normal In-Reply-To: <52940dbe$0$11089$c3e8da3@news.astraweb.com> References: <0a4ae59b-fff8-40dd-b264-823ea596ad82@googlegroups.com>, <52940dbe$0$11089$c3e8da3@news.astraweb.com> MIME-Version: 1.0 X-OriginalArrivalTime: 26 Nov 2013 03:16:10.0047 (UTC) FILETIME=[DA9264F0:01CEEA55] X-Mailman-Approved-At: Tue, 26 Nov 2013 05:06:27 +0100 X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.15 Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Newsgroups: comp.lang.python Message-ID: Lines: 112 NNTP-Posting-Host: 2001:888:2000:d::a6 X-Trace: 1385438789 news.xs4all.nl 15863 [2001:888:2000:d::a6]:58919 X-Complaints-To: abuse@xs4all.nl Xref: csiph.com comp.lang.python:60484 --_b1dfdfa0-e1eb-462d-9d6f-a6538bf0af85_ Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable Hi=2C I'm assuming you are taking a computer/network security course. Md5 hashing operation is designed to be mathematically unidirectional=2C yo= u can only attempt to find a collision situation but it's technically impos= sible to reverse the operation. With that said=2C it's possible to "crack" or "decrypt" a md5 hash value by= searching through a value-hash database to find the most commonly used pas= sword under a given hash value. You can see the tool at http://www.md5crack= .com/home. Yatong > From: steve@pearwood.info > Subject: Re: Cracking hashes with Python > Date: Tue=2C 26 Nov 2013 02:55:58 +0000 > To: python-list@python.org >=20 > On Mon=2C 25 Nov 2013 15:32:41 -0800=2C TheRandomPast wrote: >=20 > > Hi=2C > >=20 > > I have a school project to do where I've to download MD5 Hashes from a > > particular website and write a code that will crack them. >=20 > A school project. Right. Heh. :-) >=20 > And which website's hashes would this be? >=20 >=20 > > Does anyone > > know where I'll find out more information on how to do this? There's > > only 4 hashes that I need to do so it doesn't have to be a large script > > just needs to be able to download the hashes from the website. Can > > anyone help me out? >=20 > The size of the script has nothing to do with the number of hashes you=20 > have to crack. Whether it is one hash and one million=2C the script will = be=20 > exactly the same. >=20 > Do you have to write a program to download the hashes=2C or can you just= =20 > browse to the web address with your browser and save them? >=20 > If you have to write your own program=2C start here: >=20 > https://duckduckgo.com/?q=3Dpython+how+to+download+data+from+the+web >=20 >=20 > --=20 > Steven > --=20 > https://mail.python.org/mailman/listinfo/python-list = --_b1dfdfa0-e1eb-462d-9d6f-a6538bf0af85_ Content-Type: text/html; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable
Hi=2C

<= div>I'm assuming you are taking a computer/network security course.

Md5 hashing operation is designed to be mathematically unidire= ctional=2C you can only attempt to find a collision situation but it's tech= nically impossible to reverse the operation.

With that s= aid=2C it's possible to "crack" or "decrypt" a md5 hash value by searching = through a value-hash database to find the most commonly used password under= a given hash value. You can see the tool at =3Bhttp://www.md5crack.com/home.
Yatong

>=3B From: steve@pearwood.info
>=3B Subject: Re= : Cracking hashes with Python
>=3B Date: Tue=2C 26 Nov 2013 02:55:58 += 0000
>=3B To: python-list@python.org
>=3B
>=3B On Mon=2C 25= Nov 2013 15:32:41 -0800=2C TheRandomPast wrote:
>=3B
>=3B >= =3B Hi=2C
>=3B >=3B
>=3B >=3B I have a school project to do = where I've to download MD5 Hashes from a
>=3B >=3B particular websit= e and write a code that will crack them.
>=3B
>=3B A school proj= ect. Right. Heh. :-)
>=3B
>=3B And which website's hashes would = this be?
>=3B
>=3B
>=3B >=3B Does anyone
>=3B >= =3B know where I'll find out more information on how to do this? There's>=3B >=3B only 4 hashes that I need to do so it doesn't have to be a l= arge script
>=3B >=3B just needs to be able to download the hashes f= rom the website. Can
>=3B >=3B anyone help me out?
>=3B
>= =3B The size of the script has nothing to do with the number of hashes you =
>=3B have to crack. Whether it is one hash and one million=2C the scr= ipt will be
>=3B exactly the same.
>=3B
>=3B Do you have t= o write a program to download the hashes=2C or can you just
>=3B brow= se to the web address with your browser and save them?
>=3B
>=3B= If you have to write your own program=2C start here:
>=3B
>=3B = https://duckduckgo.com/?q=3Dpython+how+to+download+data+from+the+web
>= =3B
>=3B
>=3B --
>=3B Steven
>=3B --
>=3B http= s://mail.python.org/mailman/listinfo/python-list
= = --_b1dfdfa0-e1eb-462d-9d6f-a6538bf0af85_--