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Newsgroups: comp.lang.python
Date: Mon, 29 Oct 2012 21:20:44 -0700 (PDT)
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Subject: Re: date and time comparison how to
From: noydb <jenn.duerr@gmail.com>
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Xref: csiph.com comp.lang.python:32463

On Monday, October 29, 2012 11:11:55 PM UTC-4, Dave Angel wrote:
> On 10/29/2012 10:13 PM, noydb wrote:
>=20
> > I guess I get there eventually! =20
>=20
> > This seems to work
>=20
> >
>=20
> >     pdf_timeStamp =3D time.strftime("%m%d%y%H%M%S",time.localtime(os.pa=
th.getmtime(pdf)))
>=20
> >     intermediateTime =3D time.strptime(pdf_timeStamp, "%m%d%y%H%M%S")
>=20
> >     pdfFile_compareTime =3D time.mktime(intermediateTime)
>=20
> >
>=20
> > (and I'll do the same to the user entered date-n-time and then compare)
>=20
> >
>=20
> >
>=20
> > Lastly, so can anyone chime in and tell me if this is a good method or =
not?  Is there a better way?
>=20
>=20
>=20
> Please read the rest of the thread in particular the message 3 hours ago
>=20
> from Gary Herron
>=20
>=20
>=20
>                 import datetime, os, stat
>=20
>                 mtime =3D os.lstat(filename)[stat.ST_MTIME]   // the file=
s
>=20
> modification time
>=20
>                 dt =3D datetime.datetime.fromtimestamp(mtime)
>=20
>=20
>=20
> Now you can compare two datetimes simply by
>=20
>    if dt1 < dt2:
>=20
>=20
>=20
> Or you can subtract them, and examine the difference.
>=20
>=20
>=20
> What's the need for all that string conversion stuff?
>=20
>=20
>=20
>=20
>=20
>=20
>=20
> --=20
>=20
>=20
>=20
> DaveA

okay, I see.
But for the user supplied date... I'm not sure of the format just yet... te=
sting with a string for now (actual date-date might be possible, tbd later)=
, so like '10292012213000' (oct 29, 2012 9:30pm).  How would you get that i=
nput into a format to compare with dt above?