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Subject: Re: Input wont work with if statement if it has a space
From: eli m <techgeek201@gmail.com>
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Xref: csiph.com comp.lang.python:40592

On Tuesday, March 5, 2013 3:47:31 PM UTC-8, emile wrote:
> On 03/05/2013 03:33 PM, eli m wrote:
> 
> > On Tuesday, March 5, 2013 3:31:13 PM UTC-8, eli m wrote:
> 
> >> Hi guys, i have a program like this: (A lot of code is not included)
> 
> >>
> 
> >> run = 0
> 
> >>
> 
> >> while run == 0:
> 
> >>
> 
> >>     function = raw_input("Type in a function:")
> 
> >>
> 
> >>     if function == "Example":
> 
> 
> 
> whenever function isn't _exactly_ "Example" the else clause executes.
> 
> 
> 
> If you want to catch forms of example you might try:
> 
> 
> 
>      if function.strip().upper() == "EXAMPLE":
> 
> 
> 
> Emile
> 
> 
> 
> 
> 
> 
> 
> 
> 
> >>
> 
> >>        print ("Hello World!")
> 
> >>
> 
> >>     else:
> 
> >>
> 
> >>        print ("blah blah blah")
> 
> >>
> 
> >>
> 
> >>
> 
> >> The problem is that whenever i type in example with a space after it then it prints the else statement.
> 
> >>
> 
> >>
> 
> >>
> 
> >> My question is, how do i get it to except input with spaces?
> 
> >
> 
> > oops i meant function = raw_input("Type in a function:")
> 
> >

Thank you!