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Date: Thu, 06 Jun 2013 20:43:11 -0400
From: Dave Angel <davea@davea.name>
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Subject: Re: trigger at TDM/2 only
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On 06/06/2013 08:03 PM, cerr wrote:
> Hi,
>
> I have a process that I can trigger only at a certain time. Assume I have a TDM period of 10min, that means, I can only fire my trigger at the 5th minute of every 10min cycle i.e. at XX:05, XX:15, XX:25... For hat I came up with following algorithm which oly leaves the waiting while loop if minute % TDM/2 is 0 but not if minute % TDM is 0:
> 	min = datetime.datetime.now().timetuple().tm_hour*60 + datetime.datetime.now().timetuple().tm_min
> 	while not (min%tdm_timeslot != 0 ^ min%(int(tdm_timeslot/2)) != 0):

You might have spent three minutes and simplified this for us.  And in 
the process discovered the problem.

(BTW, min() is a builtin function, so it's not really a good idea to be 
shadowing it.)

You didn't give python version, so my sample is assuming Python 2.7 
For your code it shouldn't matter.

tdm = 10
tdm2 = 5

y = min(3,4)
print y

for now in range(10,32):
     print now, now%tdm, now%tdm2,
     print not(now % tdm !=0 ^ now%tdm2 !=0) #bad
     print not((now % tdm !=0) ^ (now%tdm2 !=0))  #good


Your problem is one of operator precedence.  Notice that ^ has a higher 
precedence than != operator, so you need the parentheses I added in the 
following line.

What I don't understand is why you used this convoluted approach.  Why not

     print now%tdm != tdm2

For precedence rules, see:
   http://docs.python.org/2/reference/expressions.html#operator-precedence




-- 
DaveA