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Newsgroups: comp.lang.python
Date: Sat, 2 Mar 2013 19:52:00 -0800 (PST)
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Subject: Re: Pygame mouse cursor load/unload
From: Alex Gardner <agardner210@gmail.com>
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On Saturday, March 2, 2013 9:08:18 PM UTC-6, Ian wrote:
> On Sat, Mar 2, 2013 at 6:56 PM, Alex Gardner <agardner210@gmail.com> wrot=
e:
>=20
> > I am in the process of making a pong game in python using the pygame li=
brary.  My current problem is that when I move the mouse, it turns off as s=
oon as the mouse stops moving.  The way I am doing this is by making the de=
fault cursor invisible and using .png files as replacements for the cursor.=
  Perhaps my code would best explain my problem.  I will take help in any w=
ay that I can.  Here are the links that contain my code:
>=20
>=20
>=20
> Your mouse motion code draws the paddle in the new position, waits
>=20
> 1/10th of a second, and then draws over it again with the "invisible"
>=20
> paddle.  Thus, approximately 1/10th of a second after you stop moving
>=20
> the mouse, it disappears.
>=20
>=20
>=20
> Mouse motion events are probably not the best way to do this.  You can
>=20
> instead just capture the current position of the mouse on every frame
>=20
> and use that instead.  I replaced your main loop with the following:
>=20
>=20
>=20
> paddle_pos =3D (0, 0)
>=20
> clock =3D pygame.time.Clock()
>=20
>=20
>=20
> while True:
>=20
>     for event in pygame.event.get():
>=20
>         if event.type =3D=3D QUIT:
>=20
>             sys.exit()
>=20
>=20
>=20
>     # Erase the paddle from the old mouse position.
>=20
>     screen.blit(bpaddle, paddle_pos)
>=20
>     # Redraw the net before the paddle so that the paddle can appear over=
 it.
>=20
>     pygame.draw.line(screen, game.lineColor, game.net1, game.net2,
>=20
>                      game.netWidth)
>=20
>     # Get the new mouse position.
>=20
>     paddle_pos =3D pygame.mouse.get_pos()
>=20
>     # Draw the paddle at the new mouse position.
>=20
>     screen.blit(beeper, paddle_pos)
>=20
>     # Update the screen if it's double-buffered.
>=20
>     pygame.display.update()
>=20
>     # Finally, let the CPU idle until it's time for the next frame.
>=20
>     # 50 here means that it will sleep long enough to achieve 50 FPS.
>=20
>     clock.tick(50)
>=20
>=20
>=20
> And I think you will find that this does what you want.
>=20
>=20
>=20
> A couple more observations while I'm at it.  Generally there is no
>=20
> need to be calling pygame.display.update() multiple times per frame.
>=20
> Just draw everything that you need, and then call it once at the end
>=20
> of the loop, as I have shown above.  Also, the shebang line only does
>=20
> anything if it's the very first line in the file, so it would need to
>=20
> appear before the module docstring to do anything useful.

Thank you very much, Ian.  I understand the code and have learned from it. =
 If I were more knowledgeable in python I wouldn't have had to ask; I am le=
arning as I go with this project.  Again, thank you :)