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Date: Thu, 06 Jun 2013 16:54:13 +0100
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Xref: csiph.com comp.lang.python:47237

On 06/06/2013 16:37, Chris Angelico wrote:
> On Thu, Jun 6, 2013 at 10:14 PM, Dave Angel <davea@davea.name> wrote:
>> If you're planning on having the files densely populated (meaning no gaps in
>> the numbering), then you could use a binary search to find the last one.
>> Standard algorithm would converge with 10 existence checks if you have a
>> limit of 1000 files.
>
> Or, if you can dedicate a directory to those files, you could go even simpler:
>
> dataFile = open('filename0.0.%d.json'%len(os.listdir()), 'w')
>
> The number of files currently existing equals the number of the next file.
>
Assuming no gaps.