Path: csiph.com!v102.xanadu-bbs.net!xanadu-bbs.net!feeder.erje.net!eu.feeder.erje.net!news.stack.nl!newsfeed.xs4all.nl!newsfeed1.news.xs4all.nl!xs4all!post.news.xs4all.nl!not-for-mail Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.033 X-Spam-Evidence: '*H*': 0.94; '*S*': 0.00; 'algorithm': 0.04; 'binary': 0.07; 'subject:script': 0.09; 'subject:How': 0.10; "'w')": 0.16; '(meaning': 0.16; 'from:addr:rosuav': 0.16; 'from:name:chris angelico': 0.16; 'subject:variable': 0.16; 'subject:when': 0.16; 'files.': 0.16; 'wrote:': 0.18; 'thu,': 0.19; 'file.': 0.24; 'header:In-Reply-To:1': 0.27; 'message- id:@mail.gmail.com': 0.30; 'existence': 0.31; 'subject:next': 0.31; 'subject:time': 0.33; 'could': 0.34; 'received:google.com': 0.35; 'next': 0.36; 'subject:?': 0.36; 'checks': 0.38; 'to:addr :python-list': 0.38; 'files': 0.38; 'planning': 0.38; 'pm,': 0.38; 'to:addr:python.org': 0.39; 'even': 0.60; 'dave': 0.60; "you're": 0.61; 'equals': 0.68; 'limit': 0.70; 'angel': 0.91; 'gaps': 0.93; '2013': 0.98 DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=gmail.com; s=20120113; h=mime-version:in-reply-to:references:date:message-id:subject:from:to :content-type; bh=jsEznhBviFrQJSSZWKp5BFPb7pBm+IpSpQKMWN/+r/U=; b=Lw18iy0kbLyNYY91L56aO/MzPak8l6cgVpTiZbJYjCYPK9+F3ux6NYK5MB7gsJj/9t og4iFGuooyHSttKxEN22jF4+XNkz9XhwjQfD0v4118xC1Yns9cnFvTRBT2yyzF5xKUkv aCfJG1eGT0+3oJCtaHqXfcC1qVRN98N5xHw1hN05/kCnNrV90L88h46rX2Kl5mLKb40D fIkiufc3mjS3sXs6X7XbXuWa/6pd7rms/wJneRfNNwSZ64qYIkoRIVR8V4W46a/DSG7v w/GoeRO7LknBo0FRf7H6CHB93A2ADnfGS8vP40LV2JnsjbY+krTlHnGefz2woJ145Ufg UzfA== MIME-Version: 1.0 X-Received: by 10.52.155.67 with SMTP id vu3mr19003069vdb.94.1370533036577; Thu, 06 Jun 2013 08:37:16 -0700 (PDT) In-Reply-To: <51B07D29.404@davea.name> References: <854fde32-9a5a-483e-b135-5d2c0d21b49b@googlegroups.com> <51B07D29.404@davea.name> Date: Fri, 7 Jun 2013 01:37:16 +1000 Subject: Re: How to store a variable when a script is executing for next time execution? From: Chris Angelico To: python-list@python.org Content-Type: text/plain; charset=ISO-8859-1 X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.15 Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Newsgroups: comp.lang.python Message-ID: Lines: 13 NNTP-Posting-Host: 2001:888:2000:d::a6 X-Trace: 1370533039 news.xs4all.nl 15903 [2001:888:2000:d::a6]:48169 X-Complaints-To: abuse@xs4all.nl Xref: csiph.com comp.lang.python:47233 On Thu, Jun 6, 2013 at 10:14 PM, Dave Angel wrote: > If you're planning on having the files densely populated (meaning no gaps in > the numbering), then you could use a binary search to find the last one. > Standard algorithm would converge with 10 existence checks if you have a > limit of 1000 files. Or, if you can dedicate a directory to those files, you could go even simpler: dataFile = open('filename0.0.%d.json'%len(os.listdir()), 'w') The number of files currently existing equals the number of the next file. ChrisA