Path: csiph.com!usenet.pasdenom.info!weretis.net!feeder1.news.weretis.net!feeder.erje.net!eu.feeder.erje.net!newsreader4.netcologne.de!news.netcologne.de!xlned.com!feeder5.xlned.com!news2.euro.net!newsgate.cistron.nl!newsgate.news.xs4all.nl!post.news.xs4all.nl!not-for-mail Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.007 X-Spam-Evidence: '*H*': 0.99; '*S*': 0.00; 'python.': 0.02; 'python,': 0.02; '1000.': 0.09; 'confuse': 0.09; 'filed': 0.09; 'option:': 0.09; 'overwrite': 0.09; 'record.': 0.09; 'runs,': 0.09; 'cc:addr :python-list': 0.10; 'email addr:python.org>': 0.10; 'def': 0.10; 'file,': 0.15; "'r')": 0.16; 'email addr:python.org"': 0.16; 'f.read()': 0.16; 'increment': 0.16; 'subject: \n ': 0.16; 'subject:entire': 0.16; 'suggestion.': 0.16; 'wrote:': 0.17; 'skip:{ 20': 0.17; 'subject:Issue': 0.17; 'thu,': 0.17; 'team,': 0.18; 'feb': 0.19; 'email addr:gmail.com>': 0.20; 'python?': 0.20; 'file.': 0.20; 'bit': 0.21; 'import': 0.21; 'not,': 0.21; "skip:' 40": 0.22; "user's": 0.22; '\xa0if': 0.22; '\xa0so': 0.22; 'runs': 0.22; 'cc:2**0': 0.23; 'example': 0.23; 'cc:no real name:2**0': 0.24; 'second': 0.24; 'cc:addr:python.org': 0.25; 'header:In-Reply-To:1': 0.25; '----------': 0.26; 'wrote': 0.26; 'message-id:@mail.gmail.com': 0.27; 'decide': 0.28; 'run': 0.28; 'date:': 0.29; 'reset': 0.29; 'skip:& 10': 0.29; "skip:' 10": 0.30; 'function': 0.30; 'code': 0.31; 'file': 0.32; 'could': 0.32; 'print': 0.32; 'skip:s 30': 0.33; 'date.': 0.33; 'hi,': 0.33; 'received:google.com': 0.34; 'thanks': 0.34; 'sequence': 0.35; 'pm,': 0.35; 'continue': 0.35; 'next': 0.35; 'subject:': 0.36; 'compare': 0.36; 'email addr:python.org': 0.36; 'subject:with': 0.36; 'should': 0.36; 'throughout': 0.37; 'subject:: ': 0.38; 'store': 0.38; 'from:': 0.38; 'skip:o 20': 0.38; 'some': 0.38; 'forwarded': 0.38; 'where': 0.40; 'end': 0.40; 'think': 0.40; 'your': 0.60; 'decision': 0.60; 'day,': 0.60; 'save': 0.61; 'first': 0.61; 'email name:python-list': 0.62; 'day.': 0.63; 'maximum': 0.63; 'series': 0.63; 'times': 0.63; 'more': 0.63; 'show': 0.63; '10.': 0.64; 'here': 0.65; 'date,': 0.65; 'serial': 0.66; 'subject:day': 0.66; "today's": 0.66; 'today': 0.67; 'records': 0.68; 'sales': 0.70; 'day': 0.73; '11.': 0.81; '1:00': 0.84; '2013': 0.84; 'stuff:': 0.84; '\xa0at': 0.84; 'day,\xa0': 0.91; 'good,': 0.91; 'killed': 0.91 DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=gmail.com; s=20120113; h=mime-version:x-received:in-reply-to:references:date:message-id :subject:from:to:cc:content-type; bh=xr8BHf0NSnESP2cCNsHvSxXezxHg7uKXBj0Zf9BmBnA=; b=GDlFPNo7JAMFZU7U3Ex4veUXdJQKPBTaqhjKbqRTUZdtVQu6mD/ShZcwBHKU9EXR5L gwtH0DM+TqCFBVbS4mzp1hBYUARLg8/V6VQEllANxX5ZLZcWRHPuOdyC3R53m23HVDQ0 76b1Ywg6uNF1b0caP1/8/zNN64VlJ5qR/uhobOLhFoic6aKnV6XRJ461M43VwAgkR4jj LWt7jPxJ4CztEBLuEJKjcViuts7N1mkkIGeGGKXjxG8xmeMcTbxcV+K5iFaUsA10QE4S 43VhOxs4A20hT8hk4Q4wMPVaIbNgAX98fJrxq+poIhCo2HYorrwdtb25iC51kber20+Z 0mmQ== MIME-Version: 1.0 X-Received: by 10.195.12.133 with SMTP id eq5mr12956383wjd.52.1362084090909; Thu, 28 Feb 2013 12:41:30 -0800 (PST) In-Reply-To: References: Date: Thu, 28 Feb 2013 21:41:30 +0100 Subject: Fwd: Issue with continous incrementing of unbroken sequence for a entire working day From: Morten Engvoldsen To: matt.walker.jones@gmail.com Content-Type: multipart/alternative; boundary=047d7bb04c9064980e04d6ceea8d Cc: python-list@python.org X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.15 Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Newsgroups: comp.lang.python Message-ID: Lines: 208 NNTP-Posting-Host: 2001:888:2000:d::a6 X-Trace: 1362084092 news.xs4all.nl 6928 [2001:888:2000:d::a6]:35990 X-Complaints-To: abuse@xs4all.nl Xref: csiph.com comp.lang.python:40173 --047d7bb04c9064980e04d6ceea8d Content-Type: text/plain; charset=ISO-8859-1 Hi, Okey i have wrote the below program as you suggested: import time from datetime import date def salesrecord(): serial_number = 0 sales_recrod = {'record1':'product1', 'record2':'product2','record3':'product3'} for i in sales_recrod: print sales_recrod[i] serial_number += 1 print serial_number fo = open("workfile.txt", "wb") fo.write(str(serial_number)) fo.close() with open("workfile.txt", 'r') as f: serial_number = f.read() today = date.today() salesrecord() Here i am bit confuse with where i should write the read file function to read the current serial number and date. also when i overwrite the file with current serial number, it will overwrite the date also with current date, in that case how will i compare the date. Can you please show me in my example how can i achive this.. ---------- Forwarded message ---------- From: Matt Jones To: "python-list@python.org" Cc: Date: Thu, 28 Feb 2013 13:11:38 -0600 Subject: Re: Issue with continous incrementing of unbroken sequence for a entire working day Store the day as well as the serial_number in your file. If the day is the same as today's day, use the serial_number, if not, use 1. At the end of you program write the current day and serial_number. *Matt Jones* On Thu, Feb 28, 2013 at 1:00 PM, Morten Engvoldsen wrote: Hi, thanks for youe suggestion. I think i will go for your second option: # Runs this loop until killed while True serial_number = salesrecord(serial_number) But, if i save the serial_ number value in file, then how will it decide to reset the serial number to '1' when the batch runs on next working day. What condition can be good, so that next day when the batch runs, it will know it has to reset the value 1. Also my batch will not automatcilly run whole day, this is user's decision how many times he wants to run the batch in a day. Can you elebrate more how can i do that ... ---------- Forwarded message ---------- From: Morten Engvoldsen Date: Thu, Feb 28, 2013 at 5:31 PM Subject: Issue with continous incrementing of unbroken sequence for a entire working day To: python-list@python.org Hi team, I need to run a batch of sales records and the batch has serial_number filed to store the serial number of the sales record. The serial number should be set to 1 everyday when the batch runs first time in a day and the maximum serial number could be 1000. So when the batch runs first time in a day and if it has 10 records, so the last serial number will be 10. And when the batch runs 2nd time in same day, the serial number should start from 11. In this way serial_number will increment as an unbroken series throughout the entire working day. The next day when the batch runs first time the serial number will reset to 1. Now this could be sample code how the program can count the sequence for a batch: def salesrecord(): serial_number = 1 for i in selesrecord: print first_sales_record serial_number += 1 print serial_number salesrecord() So if the batch has 10 records and last serial number of first batch is 10, then when the batch runs second time in the same day, how the 'serial_number' will get the value of 10 and then continue the serial number for the same day, then for next day again the serial number will start from 1. Can you let me know how can i achive this in python? As i am in learning phase of python, can you let me know what would be good approach to do this in python. --047d7bb04c9064980e04d6ceea8d Content-Type: text/html; charset=ISO-8859-1 Content-Transfer-Encoding: quoted-printable Hi,
Okey i have wrote the below program as you suggested:

import = time
from datetime import date

def salesrecord():
=A0=A0=A0 se= rial_number =3D 0
=A0=A0=A0 sales_recrod =3D {'record1':'pro= duct1', 'record2':'product2','record3':'pro= duct3'}
=A0=A0=A0 for i in sales_recrod:
=A0=A0=A0=A0=A0=A0=A0 print sales_recro= d[i]
=A0=A0=A0=A0=A0=A0=A0 serial_number +=3D 1
=A0=A0=A0 print seria= l_number
=A0=A0=A0 fo =3D open("workfile.txt", "wb")=
=A0=A0=A0 fo.write(str(serial_number))
=A0=A0=A0 fo.close()
=A0=A0=A0 with open("workfile.txt", 'r') as f:
=A0=A0= =A0=A0=A0=A0=A0 serial_number =3D f.read()
=A0=A0=A0 today =3D date.toda= y()
=A0=A0=A0
=A0=A0=A0

salesrecord()


Here i am b= it confuse with where i should write the read file function to read the cur= rent serial number and date. also when i overwrite the file with current se= rial number, it will overwrite the date also with current date, in that cas= e how will i=A0 compare the date. Can you please show me in my example how = can i achive this..


---------- Forwarded message ----------
From:=A0Matt Jones <<= a href=3D"mailto:matt.walker.jones@gmail.com">matt.walker.jones@gmail.com>
To:=A0"python-list= @python.org" <python-= list@python.org>
Cc:=A0
Date:=A0Thu, 28 Feb 2013 13:11:38 -0600
Subject:=A0Re: Issue w= ith continous incrementing of unbroken sequence for a entire working day
Store the day as well as the serial_number in your file. =A0If the day is the=20 same as today's day, use the serial_number, if not, use 1. =A0At the en= d=20 of you program write the current day and serial_number.

Matt Jones


On Thu, Feb 28, 2013 at 1:00 PM, Morten Engvoldsen <mortenengv@= gmail.com> wrote:
Hi,
thanks for youe suggestion. I think i will go for your s= econd option:
=A0
# Runs this loop until killed while True
<do some stuff: clean serial_number, if day c= hanged, calculate salesrecord etc.>

serial_number =3D salesrecord(serial_number)
=A0
=A0
But, if i save the serial_ number value in file, then how=A0 will it decide to reset the serial number to '1' when the batch=A0 runs on next work= ing=20 day. What condition can be good, so that next day when the batch runs,=20 it will know it has to reset the value 1.=A0 Also my batch will not=20 automatcilly run whole day, this is user's decision how many times he= =20 wants to run the batch in a day. Can you elebrate more how can i do that ...

---------- Forwarded message -------= ---
From: Morten Engvoldsen <mortenengv@gmail.com>
Date: Thu, Feb 28, 2013 at 5:31 PM
Subject: Issue with continous increme= nting of unbroken sequence for a entire working day
To: python-list@python.org


Hi tea= m,
I need to run a batch=A0of sales records and =A0the batch has=A0serial= _number filed to store the serial number of the sales record. The serial nu= mber should be set to=A0=A01 everyday when the batch runs first time in a d= ay and the maximum serial number could be 1000.
=A0
So when the batch runs first time in a day=A0and if it h= as 10 records, so the last serial number will be 10. And when the batch run= s 2nd time in same day, the serial number should start from 11.=A0 In this = way serial_number will increment as an unbroken series throughout the entir= e working day. The next day when the batch runs first time the serial numbe= r will reset to 1.

Now this could be sample code how the program can count the sequence fo= r a batch:

def salesrecord():
=A0=A0=A0 serial_number =3D 1
= =A0=A0=A0 for i in selesrecord:
=A0=A0=A0=A0=A0=A0=A0 print first_sales_= record
=A0=A0=A0=A0=A0=A0=A0 serial_number +=3D 1
=A0=A0=A0=A0=A0=A0=A0 print serial_number

salesrecord()

So if= the batch has 10 records and last serial number of first batch is 10, then= when the batch runs second time in the same day, how the 'serial_numbe= r' will get the value of 10 and then continue the serial number for the= same day,=A0 then for next day again the serial number will start from 1.<= br>
Can you let me know how can i achive this in python? As i am in learnin= g phase of python, can you let me know what would be good approach to do th= is in python.

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