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Date: Wed, 22 Jun 2011 14:00:22 +1000
Subject: Re: Unicode codepoints
From: Chris Angelico <rosuav@gmail.com>
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On Wed, Jun 22, 2011 at 1:37 PM, Saul Spatz <saul.spatz@gmail.com> wrote:
> Hi,
>
> I'm just starting to learn a bit about Unicode. I want to be able to read=
 a utf-8 encoded file, and print out the codepoints it encodes. =A0After ma=
ny false starts, here's a script that seems to work, but it strikes me as a=
wfully awkward and unpythonic. =A0Have you a better way?

Once you have your data as a Unicode string (and you seem to be using
Python 3, so 's' will be a Unicode string), wouldn't a list of its
codepoints simply be this?

for c in s:
  print('U+'+hex(ord(c))[2:])

But if you do need the codePoints() function, I'd do it as a generator.

> def codePoints(s):
> =A0 =A0''' return a list of the Unicode codepoints in the string s '''
> =A0 =A0skip =3D False
> =A0 =A0for k, c in enumerate(s):
> =A0 =A0 =A0 =A0if skip:
> =A0 =A0 =A0 =A0 =A0 =A0skip =3D False
> =A0 =A0 =A0 =A0 =A0 =A0yield ord(s[k-1:k+1])
> =A0 =A0 =A0 =A0 =A0 =A0continue
> =A0 =A0 =A0 =A0if not 0xd800 <=3D ord(c) <=3D 0xdfff:
> =A0 =A0 =A0 =A0 =A0 =A0yield ord(c)
> =A0 =A0 =A0 =A0else:
> =A0 =A0 =A0 =A0 =A0 =A0skip =3D True

Your main function doesn't even have to change - it's iterating over
the list, so it may as well iterate over the generator instead.

But I don't really understand what codePoints() does. Is it expecting
the parameter to be a string of bytes or of Unicode characters?

Chris Angelico