Path: csiph.com!newsfeed.hal-mli.net!feeder3.hal-mli.net!newsfeed.hal-mli.net!feeder1.hal-mli.net!ecngs!feeder.ecngs.de!xlned.com!feeder7.xlned.com!news2.euro.net!newsgate.cistron.nl!newsgate.news.xs4all.nl!post.news.xs4all.nl!not-for-mail Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.008 X-Spam-Evidence: '*H*': 0.98; '*S*': 0.00; 'output': 0.04; 'string.': 0.04; '21,': 0.07; 'none)': 0.07; 'def': 0.10; ':-)': 0.13; 'input:': 0.16; 'itertools': 0.16; 'oct': 0.16; 'recipe': 0.16; 'wrote:': 0.17; 'header:In-Reply-To:1': 0.25; 'message- id:@mail.gmail.com': 0.27; 'maybe': 0.29; 'received:209.85.215.46': 0.30; 'to:addr:python-list': 0.33; 'received:google.com': 0.34; 'pm,': 0.35; 'received:209.85': 0.35; 'there': 0.35; 'but': 0.36; 'received:209': 0.37; 'subject:: ': 0.38; 'to:addr:python.org': 0.39; 'header:Received:5': 0.40; 'end': 0.40; 'skip:n 10': 0.63; 'obvious': 0.71; 'subject:get': 0.81; 'to:name:python': 0.84 DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=gmail.com; s=20120113; h=mime-version:in-reply-to:references:from:date:message-id:subject:to :content-type; bh=Xdj3Xp8vixEs4sjrOoLsmCNwUrFRfM+1MwetFCglWE0=; b=Lae7PEob6kO8pYNqPd18OQEm+MSnK+mBFzYxaLRDdYCqaguLjDFNBL58dCNxLzs3Fa nxnH7ON7lnmuN2h3WA/9MBfCzMPRA3Mnxxcexa8VN6m/HWPbpO8lzKbA6qtkXTHKX+wL SATTAmg4YUe/L691Tzn6wA8Rvg63PZpdNyK3F4B3d1TtlC6Dw2/1fsV4CI/HYJpmSPVM c8LliCYWDn3n5q+H0RlmIQCMJwKoKvRGZHQGTKd0Rmj6i+5EfZcOQ6pgYVtOXP/qAn40 bKuwCSkwEmQEqDTGtm9W/nnghAwmVUfKOm87t/2aO9va1bY+jkRi7mXvAfn0xz48RPnG A9vA== MIME-Version: 1.0 In-Reply-To: References: From: Ian Kelly Date: Sun, 21 Oct 2012 12:51:51 -0600 Subject: Re: get each pair from a string. To: Python Content-Type: text/plain; charset=ISO-8859-1 X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.15 Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Newsgroups: comp.lang.python Message-ID: Lines: 32 NNTP-Posting-Host: 2001:888:2000:d::a6 X-Trace: 1350845543 news.xs4all.nl 6938 [2001:888:2000:d::a6]:53169 X-Complaints-To: abuse@xs4all.nl Xref: csiph.com comp.lang.python:31855 On Sun, Oct 21, 2012 at 12:33 PM, Vincent Davis wrote: > I am looking for a good way to get every pair from a string. For example, > input: > x = 'apple' > output > 'ap' > 'pp' > 'pl' > 'le' > > I am not seeing a obvious way to do this without multiple for loops, but > maybe there is not :-) Use the "pairwaise" recipe from the itertools docs: def pairwise(iterable): "s -> (s0,s1), (s1,s2), (s2, s3), ..." a, b = tee(iterable) next(b, None) return izip(a, b) > In the end I am going to what to get triples, quads....... also. Generalizing: def nwise(iterable, n=2): iters = tee(iterable, n) for i, it in enumerate(iters): for _ in range(i): next(it, None) return izip(*iters)