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From: jmp <jeanmichel@sequans.com>
Subject: Re: Create a .lua fle from Python
Date: Tue, 29 Sep 2015 18:32:15 +0200
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On 09/28/2015 11:41 PM, Ariel Argaņaraz wrote:
> Hi,
> This is my first post, I would like to know if a library that can help
> me with this.
>
>
> I want to parse a XML fle with Python and save the data into a Lua table
> called for example "newTable", then I want to create a "table.lua" fle
> with the "newTable" write on it.

> And  I want to create a cities_temp.lua file
>
> cities_temps ={
> ["Buenos Aires"] = 30,
> ["Seatle"] = 25,
> }
> Can anyone give some help?
>
> Thanks.
>
> --
> Ariel Argaņaraz

Use an xml parser to fetch the data from the xml file and use a template 
engine to generate the lua code.

for instance, using bs4 (beautifulsoup) for xml and jinja2 for the 
template engine:

import bs4
import jinja2

xml = """<cities>
      <city>
               <name>BuenosAires</name>
               <temperature>30</temperature>
       </city>
<city>
       <name>Seatle</name>
       <temperature>25</temperature>
</city>
</cities>"""

lua_template = """
cities_temps ={
{%- for city, temp in cities.iteritems() %}
["{{city}}"] = {{temp}},
{%- endfor %}
}"""

xmlp = bs4.BeautifulSoup(xml, 'xml')
# from xml to python dictionary
data = {city.find('name').string:city.find('temperature').string for 
city in xmlp.findAll('city')}
# from python dictionary to lua
print jinja2.Template(lua_template).render(cities=data)


will yield (python 2.7):

cities_temps ={
["BuenosAires"] = 30,
["Seatle"] = 25,
}

Cheers,

jm