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Date: Wed, 17 Oct 2012 11:33:30 -0700 (PDT)
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Subject: Re: Script for finding words of any size that do NOT contain vowels with acute diacritic marks?
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Xref: csiph.com comp.lang.python:31535

Le mercredi 17 octobre 2012 20:28:21 UTC+2, Ian a =E9crit=A0:
> On Wed, Oct 17, 2012 at 12:17 PM,  <wxjmfauth@gmail.com> wrote:
>=20
> > Not at all, I knew this. In this I decided to program like
>=20
> > this.
>=20
> >
>=20
> > Do you get it?  Yes/No  or True/False
>=20
>=20
>=20
> It's just bad style, because both 'yes' and 'no' evaluate true.
>=20
>=20
>=20
> if HasDiacritics('=E9l=E9phant'):
>=20
>     print('Correct!')
>=20
>=20
>=20
> if HasDiacritics('elephant'):
>=20
>     print('Error!')
>=20
>=20
>=20
> Prints:
>=20
>=20
>=20
> Correct!
>=20
> Error!
>=20
>=20
>=20
> You could replace the test with "if HasDiacritics('elephant') =3D=3D
>=20
> 'yes':", but why force the caller to write that out when the former
>=20
> test is more natural and less prone to error (e.g. typoing 'yes')?

I *know* all this. In my prev. msg, the goal was to emph. the
usage of *unicode.normalize()".

jmf