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Newsgroups: comp.lang.python
Date: Fri, 22 Feb 2013 07:07:13 -0800 (PST)
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Subject: Re: Checking for valid date input and convert appropriately
From: Ferrous Cranus <nikos.gr33k@gmail.com>
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Xref: csiph.com comp.lang.python:39584

=CE=A4=CE=B7 =CE=A0=CE=B1=CF=81=CE=B1=CF=83=CE=BA=CE=B5=CF=85=CE=AE, 22 =CE=
=A6=CE=B5=CE=B2=CF=81=CE=BF=CF=85=CE=B1=CF=81=CE=AF=CE=BF=CF=85 2013 3:35:3=
1 =CE=BC.=CE=BC. UTC+2, =CE=BF =CF=87=CF=81=CE=AE=CF=83=CF=84=CE=B7=CF=82 L=
ele Gaifax =CE=AD=CE=B3=CF=81=CE=B1=CF=88=CE=B5:
> Ferrous Cranus <nikos.gr33k@gmail.com> writes:
>=20
>=20
>=20
> > Let me ask it like this:
>=20
> > How can i avoid using try: except: for checkign the date but instead ch=
eck it with an if statement:
>=20
>=20
>=20
> Let me answer this way: you can't, without resorting to the simple
>=20
> helper functions I wrote in my previous message.=20
>=20
>=20
>=20
> Why do you dislike that solution?
>=20
>=20
>=20
> ciao, lele.
>=20
> --=20
>=20
> nickname: Lele Gaifax | Quando vivr=C3=B2 di quello che ho pensato ieri
>=20
> real: Emanuele Gaifas | comincer=C3=B2 ad aver paura di chi mi copia.
>=20
> lele@metapensiero.it  |                 -- Fortunato Depero, 1929.

ok, i'll just use the try: except: i was just thinking putting them all in =
the same if() statemt but apparently it cant be done.

Actually it can, but instead of try: i have to create a function:

def is_sane_date(date):
    parts =3D [int(part) for part in date.split() if part.isdigit()]
    if len(parts) =3D=3D 3 and \
         1 <=3D parts[0] <=3D 31 and \
         1 <=3D parts[1] <=3D 12 and \
         1900 <=3D parts[2] <=3D 2100:
        return True
    return False

if is_sane_date(date):
    # ...

but the try: solution is much more less hassle.