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Subject: Re: Checking for valid date input and convert appropriately
From: Ferrous Cranus <nikos.gr33k@gmail.com>
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Xref: csiph.com comp.lang.python:39518

=CE=A4=CE=B7 =CE=A0=CE=B1=CF=81=CE=B1=CF=83=CE=BA=CE=B5=CF=85=CE=AE, 22 =CE=
=A6=CE=B5=CE=B2=CF=81=CE=BF=CF=85=CE=B1=CF=81=CE=AF=CE=BF=CF=85 2013 2:57:0=
3 =CF=80.=CE=BC. UTC+2, =CE=BF =CF=87=CF=81=CE=AE=CF=83=CF=84=CE=B7=CF=82 M=
ichael Ross =CE=AD=CE=B3=CF=81=CE=B1=CF=88=CE=B5:
> On Fri, 22 Feb 2013 01:12:40 +0100, Ferrous Cranus <nikos.gr33k@gmail.com=
> =20
> wrote:

> > Please i have been trying hours for this:

> Don't do that: Spending hours on being stuck. Take a break. Call it a =20
>=20
> night.
>=20
> Brain needs time to unstick itself.

> Besides:

> >>> from datetime import date

> >>> entry=3D'31 03 2013'

> >>> day, month, year =3D int(entry[:2]), int(entry[3:5]), int(entry[6:])
>=20
>=20
>=20
> >>> mydate=3Ddate(year,month,day)

> >>> mydate.strftime('%Y-%m-%d')
>=20
> '2013-03-31'

Tis seems very nice solution but also we need to check the user input for v=
alidity. What if the user entered: 29 15 2013 ?

i tried to use your method applying some date validation check but that als=
o failed for me:

try:
       if( datetime.strptime(date, '%d m% %Y') ):
	    day, month, year =3D int(date[:2]), int(date[3:5]), int(date[6:])
            date =3D date(year, month, day)
	    date =3D date.strftime('%Y-%m-%d')
except:
        print "....."
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D

Isn't method strptime check the user input for validity?