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From: Ian Kelly <ian.g.kelly@gmail.com>
Date: Thu, 21 Feb 2013 17:19:05 -0700
Subject: Re: Confusing math problem
To: Python <python-list@python.org>
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Xref: csiph.com comp.lang.python:39502

On Thu, Feb 21, 2013 at 4:41 PM, Schizoid Man <schiz_man@21stcentury.com> wrote:
> So how is operator.pow() different from just pow()?

math.pow() is a wrapper around the C library function.

** and operator.pow() are the same thing; the latter is just a
function version of the former.

The built-in pow() is a mutant version that takes either 2 or 3
arguments.  With 2 arguments, pow(a, b) is again equivalent to a ** b.
 With 3 arguments, pow(a, b, c) is equivalent to but more efficient
than a ** b % c, but a and b are restricted to integers.