Path: csiph.com!x330-a1.tempe.blueboxinc.net!usenet.pasdenom.info!weretis.net!feeder4.news.weretis.net!feeds.phibee-telecom.net!newsfeed.xs4all.nl!newsfeed5.news.xs4all.nl!xs4all!post.news.xs4all.nl!not-for-mail Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.008 X-Spam-Evidence: '*H*': 0.98; '*S*': 0.00; 'python': 0.08; '>>>>': 0.09; 'matt': 0.09; 'suggestion.': 0.09; 'subject:python': 0.11; 'am,': 0.12; '"copyright",': 0.16; '"credits"': 0.16; '"license"': 0.16; '[gcc': 0.16; 'linux2': 0.16; 'subject:expression': 0.16; 'subject:regular': 0.16; 'wrote:': 0.16; 'subject:Help': 0.17; 'figure': 0.21; 'jason': 0.21; "doesn't": 0.22; 'header:In-Reply- To:1': 0.22; 'guess': 0.26; 'skip:[ 10': 0.27; 'work.': 0.27; 'problem': 0.28; 'import': 0.28; 'accessible': 0.29; 'matches': 0.29; 'match': 0.30; 'times.': 0.30; 'thanks': 0.30; "skip:' 10": 0.30; 'apr': 0.32; 'expression': 0.32; 'hi,': 0.32; 'me?': 0.32; 'it.': 0.33; "can't": 0.33; 'to:addr:python-list': 0.33; 'header :User-Agent:1': 0.34; 'message-id:@gmail.com': 0.34; 'supposed': 0.35; 'another': 0.37; 'but': 0.37; 'received:128': 0.38; 'some': 0.38; 'received:google.com': 0.38; 'received:209.85': 0.38; 'subject:: ': 0.39; 'i.e.': 0.39; 'getting': 0.39; 'subject:with': 0.39; 'data': 0.39; 'why': 0.39; 'to:addr:python.org': 0.39; 'greatly': 0.40; 'more': 0.60; 'expert': 0.62; 'bear': 0.80; 'me:': 0.84; 'data)': 0.91 DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=gmail.com; s=gamma; h=message-id:date:from:user-agent:mime-version:to:subject:references :in-reply-to:content-type:content-transfer-encoding; bh=nmAiiTaG5DJgmUzHJUSTieftLI5TG9os/VvehIAGUVI=; b=B9PYApnLQUs0NMd7u44n/0OZ8p8TksyMhjY6lmb4Z8GFQo1aVNgSfvarn8FB/CO3DF l+LH+Ya7trHwN9r1MJwNoCkZbZq8Kq+Htr+6tsrNQU8IK2BZXI7g2tAUaRQs5jS3H4VP kFKINwysoEqmYfOmDP8oCYmW90vXxD1IYQ7YY= Date: Fri, 19 Aug 2011 09:20:16 -0600 From: Matt Funk User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64; rv:6.0) Gecko/20110812 Thunderbird/6.0 MIME-Version: 1.0 To: python-list@python.org Subject: Re: Help with regular expression in python References: <201108181349.54727.matze999@gmail.com> <201108181703.06278.matze999@gmail.com> <201108190809.17040.matze999@gmail.com> In-Reply-To: Content-Type: text/plain; charset=ISO-8859-1 Content-Transfer-Encoding: 7bit X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.12 Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Newsgroups: comp.lang.python Message-ID: Lines: 42 NNTP-Posting-Host: 2001:888:2000:d::a6 X-Trace: 1313767221 news.xs4all.nl 23965 [2001:888:2000:d::a6]:43235 X-Complaints-To: abuse@xs4all.nl Xref: x330-a1.tempe.blueboxinc.net comp.lang.python:11847 Hi, thanks for the suggestion. I guess i had found another way around the problem as well. But i really wanted to match the line exactly and i wanted to know why it doesn't work. That is less for the purpose of getting the thing to work but more because it greatly annoys me off that i can't figure out why it doesn't work. I.e. why the expression is not matches {32} times. I just don't get it. anyway, thanks though matt On 8/19/2011 8:41 AM, Jason Friedman wrote: >> Hi Josh, >> thanks for the reply. I am no expert so please bear with me: >> I thought that the {32} was supposed to match the previous expression 32 >> times? >> >> So how can i have all matches accessible to me? > $ python > Python 2.6.5 (r265:79063, Apr 16 2010, 13:57:41) > [GCC 4.4.3] on linux2 > Type "help", "copyright", "credits" or "license" for more information. >>>> data > '1.002000e+01 2.037000e+01 2.128000e+01 1.908000e+01 1.871000e+01 > 1.914000e+01 2.007000e+01 1.664000e+01 2.204000e+01 2.109000e+01 > 2.209000e+01 2.376000e+01 2.158000e+01 2.177000e+01 2.152000e+01 > 2.267000e+01 1.084000e+01 1.671000e+01 1.888000e+01 1.854000e+01 > 2.064000e+01 2.000000e+01 2.200000e+01 2.139000e+01 2.137000e+01 > 2.178000e+01 2.179000e+01 2.123000e+01 2.201000e+01 2.150000e+01 > 2.150000e+01 2.199000e+01 : (instance: 0) : some > description' >>>> import re >>>> re.findall(r"\d\.\d+e\+\d+", data) > ['1.002000e+01', '2.037000e+01', '2.128000e+01', '1.908000e+01', > '1.871000e+01', '1.914000e+01', '2.007000e+01', '1.664000e+01', > '2.204000e+01', '2.109000e+01', '2.209000e+01', '2.376000e+01', > '2.158000e+01', '2.177000e+01', '2.152000e+01', '2.267000e+01', > '1.084000e+01', '1.671000e+01', '1.888000e+01', '1.854000e+01', > '2.064000e+01', '2.000000e+01', '2.200000e+01', '2.139000e+01', > '2.137000e+01', '2.178000e+01', '2.179000e+01', '2.123000e+01', > '2.201000e+01', '2.150000e+01', '2.150000e+01', '2.199000e+01']