Path: csiph.com!x330-a1.tempe.blueboxinc.net!usenet.pasdenom.info!weretis.net!feeder1.news.weretis.net!feeder.erje.net!newsfeed.xs4all.nl!newsfeed5.news.xs4all.nl!xs4all!newsgate.cistron.nl!newsgate.news.xs4all.nl!post.news.xs4all.nl!not-for-mail Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.002 X-Spam-Evidence: '*H*': 1.00; '*S*': 0.00; 'subject:two': 0.07; 'received:80.91': 0.09; 'received:80.91.229': 0.09; 'received:80.91.229.12': 0.09; 'received:gmane.org': 0.09; 'received:list': 0.09; 'received:lo.gmane.org': 0.09; 'tuple': 0.09; 'elements,': 0.16; 'received:173.11': 0.16; 'subject:list': 0.18; '>>>': 0.18; 'header:In-Reply-To:1': 0.22; 'separate': 0.28; 'lists': 0.28; 'subject:?': 0.31; 'list': 0.32; 'there': 0.33; 'to:addr:python-list': 0.33; '...': 0.34; 'header:User-Agent:1': 0.34; 'header:X-Complaints-To:1': 0.35; 'subject:lists': 0.36; 'two': 0.37; 'received:org': 0.38; 'subject:: ': 0.39; 'header :Mime-Version:1': 0.39; 'to:addr:python.org': 0.39 X-Injected-Via-Gmane: http://gmane.org/ To: python-list@python.org From: Emile van Sebille Subject: Re: how to separate a list into two lists? Date: Sat, 06 Aug 2011 10:24:10 -0700 References: Mime-Version: 1.0 Content-Type: text/plain; charset=ISO-8859-1; format=flowed Content-Transfer-Encoding: 7bit X-Gmane-NNTP-Posting-Host: 173-11-108-137-sfba.hfc.comcastbusiness.net User-Agent: Mozilla/5.0 (Windows NT 5.1; rv:5.0) Gecko/20110624 Thunderbird/5.0 In-Reply-To: X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.12 Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Newsgroups: comp.lang.python Message-ID: Lines: 17 NNTP-Posting-Host: 2001:888:2000:d::a6 X-Trace: 1312651348 news.xs4all.nl 23908 [2001:888:2000:d::a6]:47726 X-Complaints-To: abuse@xs4all.nl Xref: x330-a1.tempe.blueboxinc.net comp.lang.python:10978 On 8/6/2011 10:07 AM smith jack said... > if a list L is composed with tuple consists of two elements, that is > L = [(a1, b1), (a2, b2) ... (an, bn)] > > is there any simple way to divide this list into two separate lists , such that > L1 = [a1, a2... an] > L2=[b1,b2 ... bn] > >>> L = [('a1', 'b1'), ('a2', 'b2'),('an', 'bn')] >>> zip(*L) [('a1', 'a2', 'an'), ('b1', 'b2', 'bn')] Emile