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From: =?UTF-8?B?Q2hyaXMg4oCcS3dwb2xza2HigJ0gV2Fycmljaw==?= <kwpolska@gmail.com>
Date: Tue, 21 May 2013 21:06:11 +0200
Subject: Re: PEP 378: Format Specifier for Thousands Separator
To: Carlos Nepomuceno <carlosnepomuceno@outlook.com>
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On Tue, May 21, 2013 at 8:49 PM, Carlos Nepomuceno
<carlosnepomuceno@outlook.com> wrote:
> Thank you, but let me rephrase it. I'm already using str.format() but I'd=
 like to use '%' (BINARY_MODULO) operator instead.

There is no real reason to do this.  `str.format()` is the new shiny
thing you should be using all the time.  Also, '%' is BINARY_MODULO
(where did you even get that name from?) if and only if you have two
numbers, and it performs the modulo division (eg. 27 % 5 =3D 2)

> So, the question is: Where would I change the CPython 2.7.5 source code t=
o enable '%' (BINARY_MODULO) to format using the thousands separator like s=
tr.format() does, such as:
>
>>>>sys.stderr.write('%,d\n' % 1234567)
> 1,234,567

This will make your code unportable and useless, depending on one
patch you made.  Please don=E2=80=99t do that.  Instead,

> >>> sys.stdout.write('Number =3D %s\n' % '{:,.0f}'.format(x))
> Number =3D 12,345
>
> 'x' is unsigned integer so it's like using a sledgehammer to crack a nut!

In Python?  Tough luck, every int is signed.  And it isn=E2=80=99t just a
sledgehammer, it=E2=80=99s something worse.  Just do that:

>>> sys.stdout.write('Number =3D {:,.0f}\n'.format(x))

Much more peaceful.

You can also do a print, like everyone sane would.  Where did you
learn Python from?  =E2=80=9CPython Worst Practice for Dummies=E2=80=9D?

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