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To: python-list@python.org
From: Peter Otten <__peter__@web.de>
Subject: Re: Python - parsing nested information and provide it in proper format from log file
Date: Fri, 20 Feb 2015 15:27:59 +0100
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jt11380@gmail.com wrote:

> On Friday, February 20, 2015 at 8:11:59 AM UTC-5, Peter Otten wrote:
>> Jay T wrote:
>> 
>> >  have some log file which has nested data which i want to filter and
>> >  provide specific for student with total counts
>> > 
>> > Here is my log file sample:
>> > Student name is ABC
>> > Student age is 12
>> > student was late
>> > student was late
>> > student was late
>> > Student name is DEF
>> > student age is 13
>> > student was late
>> > student was late
>> > 
>> > i want to parse and show data as Student name, student age , number of
>> > counts how many times student was late e:g Name Age TotalCount
>> > ABC 12   3
>> > DEF 13    2
>> > 
>> > Please help me with solution that will be really grateful.
>> 
>> What have you tried? Please show us some code.
>> 
>> The basic idea would be to iterate over the lines and split the current
>> line into words.
>> 
>> If the second word is "name" and it's not the first iteration print the
>> student's name, age, and was_late count. Then set the name variable to
>> the new name and reset age and was_late to 0. To detect the first
>> iteration you can set
>> 
>> name = None
>> 
>> before you enter the loop and then check for that value before printing:
>> 
>> if name is not None:
>>     ... # print student data
>> 
>> If the second word is "age" convert the 4th word to integer and set the
>> age variable.
>> 
>> If the second word is "was" increment the was_late counter.
>> 
>> Remember that when the loop ends and the file was not empty you have one
>> more student's data to print.


> Now get stuck to get count for total_late time as it is part of name, age
> so how to write logic which counts as a part of group.
> 
> any help will be grateful.

Try to write code that does what I describe in my outline. Initialise name 
before the loop and dump the collected data when you encounter a new name.

name = None
total_late = 0
age = "unknown"

with open("student.txt") as instream:
    for line in instream:
        words = line.split()
        if words[1] == "name":
            if name is not None:
                print name, age, total_late
            name = " ".join(words[3:])
            age = "unknown"
            total_late = 0
        elif words[1] == "was":
            total_late += 1
        elif words[1] == "age":
            age = int(words[3])
        else:
            print "don't know what to do with line %r" %line
if name is not None:
    print name, age, total_late

Checking whole words has the advantage that there will be no match if the 
string "name" or "age" is part of the student's name.

> I tried to implent below code and got stucked how to do nested loop to
> count instead doing another logic and parsing:
> 
> import re
> def GetName(input_string):
>                   myName=input_string.split()
>                   myName1= myName[1]

That's the wrong index.

>                   return myName1
> def GetAge(input_string):
>                   myAge=input_string.split()
>                   myAge1= myAge[2]

That's the wrong index.

>                   return myAge1

In general you should test your functions independently from the whole 
program. That way you can build on known-good components and thus reduce the 
area where to look for remaining bugs.
                      
> file = open('mylogfile')
> log_data = file.readlines()

The file is probably short enough that it doesn't matter here, but iterating 
over the file directly is good habit to get into. Example:

with open("mylogfile") as log_data:
   for eachline in log_data:
       ...

> print 'entered'
> for eachline in log_data:
>            input_string = eachline
>            if 'name' in input_string:
>                     sometextval = GetName(input_string)
>                     print "name", sometextval
>            if 'Age' in input_string:

This test is problematic because Python takes case into account when 
comparing strings:

>>> "age" == "AGE"
False
>>> s = "RAGE"
>>> "age" in s
False

If case isn't consistent you should convert the string to lowercase:

>>> "age" == "AGE".lower()
True
>>> "age" in s.lower()
True

>                      sometextval2 = GetAge(input_string)
>                      print "Age", sometextval2
>