Path: csiph.com!v102.xanadu-bbs.net!xanadu-bbs.net!feeder.erje.net!eu.feeder.erje.net!newsfeed.fsmpi.rwth-aachen.de!newsfeed.straub-nv.de!weretis.net!feeder4.news.weretis.net!ecngs!feeder2.ecngs.de!217.188.199.168.MISMATCH!takemy.news.telefonica.de!telefonica.de!newsfeed.xs4all.nl!newsfeed4a.news.xs4all.nl!xs4all!newsgate.cistron.nl!newsgate.news.xs4all.nl!post.news.xs4all.nl!not-for-mail Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.005 X-Spam-Evidence: '*H*': 0.99; '*S*': 0.00; 'skip:[ 20': 0.04; 'yet.': 0.04; '0),': 0.16; '24,': 0.16; 'from:addr:mrabarnett.plus.com': 0.16; 'from:addr:python': 0.16; 'from:name:mrab': 0.16; 'interval.': 0.16; 'message-id:@mrabarnett.plus.com': 0.16; 'received:192.168.1.4': 0.16; 'skip:[ 30': 0.16; 'there!': 0.16; 'vars:': 0.16; 'wrote:': 0.18; 'trying': 0.19; 'example': 0.22; 'header:User-Agent:1': 0.23; 'header:In-Reply-To:1': 0.27; 'grouping': 0.31; 'values.': 0.31; 'subject:time': 0.33; 'skip:d 20': 0.34; 'could': 0.34; 'objects': 0.35; 'two': 0.37; 'list': 0.37; 'to:addr:python-list': 0.38; '12,': 0.39; 'to:addr:python.org': 0.39; 'days': 0.60; 'email addr:gmail.com': 0.63; 'here': 0.66; 'skip:r 30': 0.69 X-CM-Score: 0.00 X-CNFS-Analysis: v=2.1 cv=A/HiPsmG c=1 sm=1 tr=0 a=0nF1XD0wxitMEM03M9B4ZQ==:117 a=0nF1XD0wxitMEM03M9B4ZQ==:17 a=0Bzu9jTXAAAA:8 a=Vhvw94NMJWsA:10 a=IkcTkHD0fZMA:10 a=EBOSESyhAAAA:8 a=pGLkceISAAAA:8 a=EN1oexMKevY2K_mYtCkA:9 a=-VQNqaJfEAReKZCT:21 a=OCIlZx_NNdTQHuZR:21 a=QEXdDO2ut3YA:10 X-AUTH: mrabarnett@:2500 Date: Thu, 12 Feb 2015 13:17:42 +0000 From: MRAB User-Agent: Mozilla/5.0 (Windows NT 6.3; WOW64; rv:31.0) Gecko/20100101 Thunderbird/31.4.0 MIME-Version: 1.0 To: python-list@python.org Subject: Re: Group by interval time References: <6f6f567d-7e25-4a74-96ef-d20cb44a9646@googlegroups.com> In-Reply-To: <6f6f567d-7e25-4a74-96ef-d20cb44a9646@googlegroups.com> Content-Type: text/plain; charset=utf-8; format=flowed Content-Transfer-Encoding: 7bit X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.15 Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Newsgroups: comp.lang.python Message-ID: Lines: 22 NNTP-Posting-Host: 2001:888:2000:d::a6 X-Trace: 1423747073 news.xs4all.nl 2832 [2001:888:2000:d::a6]:41533 X-Complaints-To: abuse@xs4all.nl Xref: csiph.com comp.lang.python:85580 On 2015-02-12 12:34, charles.sartori@gmail.com wrote: > Hello there! > > I`m trying to group by a list of Row() objects in 12days interval and sum(). values. Here is an example of the list > > [Row(time=datetime.datetime(2013, 1, 1, 0, 0), sum=4676557380615), Row(time=datetime.datetime(2013, 1, 2, 0, 0), sum=6549630855895), Row(time=datetime.datetime(2013, 1, 3, 0, 0), sum=6549630855895), ...] > > Row() objects has two vars: row.time and row.sum > > > The result that I`m looking for is: > [[datetime.datetime(2013, 1, 1, 0, 0), value], > [datetime.datetime(2013, 1, 12, 0, 0), value], > [datetime.datetime(2013, 1, 24, 0, 0), value] > ] > Where value is the sum() of all row.sum in that interval. > > I`m trying to use itertools.groupby by I could not get it to work yet. > Try grouping by the number of days since datetime.datetime(2013, 1, 1, 0, 0), integer-divided by 12.