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Date: Thu, 16 May 2013 16:14:27 +0100
Subject: Re: spilt question
From: =?ISO-8859-1?Q?F=E1bio_Santos?= <fabiosantosart@gmail.com>
To: loial <jldunn2000@gmail.com>
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str.split takes a limit argument. Try your_string.split('_', 1)
On 16 May 2013 16:11, "loial" <jldunn2000@gmail.com> wrote:

> I want to split a string so that I always return everything BEFORE the
> LAST underscore
>
> HELLO_xxxxxxxx.lst         # should return HELLO
> HELLO_GOODBYE_xxxxxxxx.ls  # should return HELLO_GOODBYE
>
> I have tried with rsplit but cannot get it to work.
>
> Any help appreciated
>
> --
> http://mail.python.org/mailman/listinfo/python-list
>

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<p dir=3D"ltr"> str.split takes a limit argument. Try your_string.split(&#3=
9;_&#39;, 1)</p>
<div class=3D"gmail_quote">On 16 May 2013 16:11, &quot;loial&quot; &lt;<a h=
ref=3D"mailto:jldunn2000@gmail.com">jldunn2000@gmail.com</a>&gt; wrote:<br =
type=3D"attribution"><blockquote class=3D"gmail_quote" style=3D"margin:0 0 =
0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
I want to split a string so that I always return everything BEFORE the LAST=
 underscore<br>
<br>
HELLO_xxxxxxxx.lst =A0 =A0 =A0 =A0 # should return HELLO<br>
HELLO_GOODBYE_xxxxxxxx.ls =A0# should return HELLO_GOODBYE<br>
<br>
I have tried with rsplit but cannot get it to work.<br>
<br>
Any help appreciated<br>
<br>
--<br>
<a href=3D"http://mail.python.org/mailman/listinfo/python-list" target=3D"_=
blank">http://mail.python.org/mailman/listinfo/python-list</a><br>
</blockquote></div>

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